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irina1246 [14]
2 years ago
14

Please help with khan

Mathematics
1 answer:
kodGreya [7K]2 years ago
3 0

Answer:

not 100% but I think it's Step 1

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1) how many significant digits are there in the sum of 45.10 and 102.203?
Sergio039 [100]
Oi  :)

1) There are 3 significant digits
45.10+102.203= 147.303

2)
15 Mi/h  =  22 ft/s

3)
C= 72*m* \frac{3}{4} \\  \\ C= 72*81* \frac{3}{4} \\  \\ C= \frac{17496}{4}  \\  \\ C=4374

4)
There are 4 significant digitis. Leter C 
7 0
3 years ago
Lisa reads an equal number of pages of a book every week. The graph below shows the number of pages of the book left to read, y,
iren [92.7K]

9514 1404 393

Answer:

  (a)  y = −50x + 250

Step-by-step explanation:

In case you don't realize that the graph starts at 250 and decreases by 50 for each increase of 1 in x, you can see if any of the equations match the given points. The only one that does is the first one:

  y = -50x +250

4 0
3 years ago
mrs. Hudson invested $700 into an account that draws 3% interest, compounded annually. what is the total value of the account af
nadezda [96]
700 x .03 x 20 = 420
420 + 700
1120 is in the account after 20 years
7 0
3 years ago
A designer enlarged both the length and the width of a rectangular carpet by 60 percent. The new carpet was too large so the des
Snowcat [4.5K]

x= length, y=width

Both the length and width were increased by 60% so now they are:

1.6x and 1.6y

Then they were both reduced by 25% so now they are 75%(100-25) of their previous size so they are:

0.75(1.6x) and 0.75(1.6y)

Their area would be length * width so it would be:

0.75(1.6x) * 0.75(1.6y)

Simplified this would be:

1.2x * 1.2y

Simplified more it would be :

1.44xy which is also 144% of xy which is a 44% increase of the original area (xy)


So the answer is:

44%



5 0
3 years ago
1 point) Are the functions f,g, and h given below linearly independent? f(x)=e3x+cos(5x), g(x)=e3x−cos(5x), h(x)=cos(5x). If the
Fynjy0 [20]

Answer:

Functions are linearly dependent (are not linearly independent.)

Step-by-step explanation:

Remember that two functions f(x), g(x) and h(x) are said linearly independent on an interval I if the <em>only solution</em> to the equation

\alpha f(x)+\beta g(x)+\omega h(x)=0, \ \text{for all } x\in I

is the trivial one: α = 0, β = 0, ω = 0. If they are not linearly independent, they are called linearly dependent.

Now, let f(x), g(x) and h(x) be the functions:

f(x)=e^{3x}+\cos(5x),

g(x)=e^{3x}-\cos(5x),

h(x)=\cos(5x).

Then, letting α = 1, β= -1 and ω = -2, we see that:

\alpha f(x)+\beta g(x)+ \omega h(x)=e^{3x}+\cos(5x)-e^{3x}+\cos(5x)+2\cos(5x)=0.

Hence, the functions f(x), g(x) and h(x) are not linearly independent, or equivalently, are linearly dependent.

8 0
3 years ago
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