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4 years ago

6

Write 3x+4y=58 and 1x+3y=36 using elimination

1 answer:

Triss [41]4 years ago

5 0

DENOTING
Eqn 1: 3x+4y=58
Eqn 2: 1x+3y=36

TRANSLATING
(Multiply Eqn 2 by 3)
Eqn 3: 3x+9y=108

ELIMINATION
(Subtract Eqn 3 from Eqn 2)
Eqn 4: -5y=-50

Divide both sides by -5 to derive the value of y.
y=10

SUBSTITUTION
(Substitute the value of y to any of the first two equations)

3x+4(3)=58
3x=58-12
3x=46
x=46/3 or 15 1/3

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<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
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Addition
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Left to Right

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