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jeka94
3 years ago
6

Probability question

Mathematics
1 answer:
Lorico [155]3 years ago
5 0
N = 45
Sample size = 6

\text {Number of combination = } C(45, 6) =  \dfrac{45!}{6!39!} = 8 145, 060

Answer:  8 145, 060
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3 years ago
Suppose that 10% of all homeowners in an earthquake-prone area of California are insured against earthquake damage. Four homeown
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Remainder of question:

Find the probability distribution of x

Answer:

The random variable x is defined as: X = {0, 1, 2, 3, 4}

The probability distribution of X:

P(X = 0) = 0.656

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P(X=3) = 0.0036

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Step-by-step explanation:

Sample size, n = 4

Random variable, X = {0, 1, 2, 3, 4}

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Proportion of homeowners who are not insured against earthquake, q = 1 - 0.1

q = 0.9

Probability distribution of x,

P(X = r) = ^nC_r *p^r q^{n-r} \\\\P(X= 0) =(^4C_0 *p^1 q^4 )\\P(X=0) = (^4C_0 *0.1^0 0.9^4 ) = 0.656\\P(X= 1)= (^4C_1 *p^1 q^3 )\\P(X=1) = (^4C_1 *0.1^1 0.9^3 ) = 0.2916\\P(X= 2)=( ^4C_2 *p^2 q^2) \\P(X=2) = (^4C_2 *0.1^2 0.9^2 ) = 0.0486\\P(X= 3) = (^4C_3 *p^3 q^3) \\ P(X=3) = (^4C_3 *0.1^3 0.9^1 ) = 0.0036\\P(X= 4) =  (^4C_4 *p^4 q^0 )\\ P(X=4) =(^4C_4 *0.1^4 0.9^0 ) = 0.0001

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3 years ago
Item 12
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8 0
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2 years ago
X2 – 2x – 17 = 0<br> Factoring
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Answer:

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