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3 years ago

HELP PLEASE!:/

Mathematics

2 answers:

Alisiya [41]3 years ago

8 0

Answer:

Option A is correct.

Step-by-step explanation:

Area of the Dart Board = 30000 mm²

Area of the Bull's eye = 700 mm²

We have to find the probability of getting a bull's eye.

$Probability=\frac{Number\:of\:favorable\:outcome}{Number\:of\:total outcome}=\frac{700}{30000}=\frac{7}{300}$

Now we convert this probability in percentage,

$percentage=\frac{7}{300}\times100=\frac{7}{3}=2.3$

Therefore, Option A is correct.

Hoochie [10]3 years ago

7 0

P(bull's-eye) = 700/30000 x 100% = 2.33% ≈ 2%

option A is the correct answer.

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In 2015 there were 759 laptops at lightning high school starting a 2016 the school box 75 more laptops at the end of each year t

nikdorinn [45]

Answer:

Step-by-step explanation:

Given the following :

Number of laptops in 2015 = 759

t(x) = 75x + 759 ; model to determine number of laptops at the school. X years after 2015.

Number of laptops in the school in 2020:

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3 years ago

A competitive knitter is knitting a circular place mat. The radius of the mat is given by the formula

Ilia_Sergeevich [38]

Answer: A. $A'(t)=\frac{4356\pi}{(t+11)^{3}}-\frac{527076\pi}{(t+11)^{5}}$

B. A'(5) = 1.76 cm/s

Step-by-step explanation: Rate of change measures the slope of a curve at a certain instant, therefore, rate is the derivative.

A. Area of a circle is given by

$A=\pi.r^{2}$

So to find the rate of the area:

$\frac{dA}{dt}=\frac{dA}{dr}.\frac{dr}{dt}$

$\frac{dA}{dr} =2.\pi.r$

Using $r(t)=3-\frac{363}{(t+11)^{2}}$

$\frac{dr}{dt}=\frac{726}{(t+11)^{3}}$

Then

$\frac{dA}{dt}=2.\pi.r.[\frac{726}{(t+11)^{3}}]$

$\frac{dA}{dt}=2.\pi.[3-\frac{363}{(t+11)^{2}}].\frac{726}{(t+11)^{3}}$

Multipying and simplifying:

$\frac{dA}{dt}=\frac{4356\pi}{(t+11)^{3}} -\frac{527076\pi}{(t+11)^{5}}$

The rate at which the area is increasing is given by expression $A'(t)=\frac{4356\pi}{(t+11)^{3}} -\frac{527076\pi}{(t+11)^{5}}$ .

B. At t = 5, rate is:

$A'(5)=\frac{4356\pi}{(5+11)^{3}} -\frac{527076\pi}{(5+11)^{5}}$

$A'(5)=\frac{4356\pi}{4096} -\frac{527076\pi}{1048576}$

$A'(5)=\frac{2408693760\pi}{4294967296}$

$A'(5)=1.76268$

At 5 seconds, the area is expanded at a rate of 1.76 cm/s.

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2 years ago

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kodGreya [7K]

Hi I don’t really understand can you explain a little bit please

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2 years ago

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anzhelika [568]

Answer:

See below

Step-by-step explanation:

Remember that quadratic functions are parabolas when graphed. The solutions are where the parabola crosses the x-axis.

1. The vertex of the parabola in f(x) is (0, 9) which is above the x-axis and the parabola opens up. So the parabola does not cross the x-axis. Therefore the solutions are imaginary.

2. The vertex of the parabola in g(x) is (9, 0) which is on the x-axis and parabola opens up. Therefore, there is a double solution.

3. The vertex of the parabola in h(x) is (-1, -9) which is below the x-axis and the parabola opens up. Therefore, there are two real solutions.

I know this is a long explanation, but that is a way of looking at the problem.

6 0

2 years ago

4. Stephanie breaks on average 1.5 pencils every school day. How many pencils can she expect to break in a week (5 days)?

olya-2409 [2.1K]

Answer:

7.5 pencils broken in a week (5 days).

Step-by-step explanation:

1.5 pencils broken a day

Now we just multiple this by 5 for each of the school day's.

1.5 pencils * 5 days = 7.5 pencils broken in a week.

Have a nice day! :)

Please mark this answer as brainiest!

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2 years ago