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3 years ago

How many carbon monoxide molecules are in 0.75 moles of carbon monoxide?

Mathematics

1 answer:

Mrac [35]3 years ago

7 0

No of molecules = no of moles x avogadro’s number

0.75 ( 6.02 × 10²³) = 4.515 x 10²³ (standard from)

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Only two percent of the world has<br> green eyes. Write 2% as a decimal.

ankoles [38]

The decimal would be 0.2

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3 years ago

Read 2 more answers

Interpret the slope based on the chart.

bogdanovich [222]

Answer:

b. For 100 additional burglaries in California one expects to see an increase of about 3 burglaries in Hawaii.

Step-by-step explanation:

The slope gives the increase in the independent variable per unit increase in the dependent variable. Hence, a reasonable interpretation for the slope would be ;

the rate of change in the number of burglaries in Hawaii per 100 unit change in number of burglaries in California is 3.

Hence, for 100 additional burglaries in California, the rate of change in the number of burglaries in Hawaii is 3.

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2 years ago

Michael is 4 years younger than twice his cousin, Damien’s age. The sum of their ages is 46. How old is Damien?

Verizon [17]

Let x = The age of Michael
Let 2x-3 = The age of Michaels cousin
X+2x-3=46
x=16+1/3
X = 49 years

I think that’s the answer I’m not 100% sure though

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3 years ago

Krutika and Natasha win some money and share it in the ratio 3:4. Krutika gets £39. How much did Natasha get?

grin007 [14]

Answer:

22.28 Pounds

Step-by-step explanation:

Add 3+4=7

39 ÷ 7=5.57

Because Natasha has the ratio of 4 she would get

5.57 × 4=22.28

Answer=22.28

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2 years ago

If P is the orthocenter of △ABC, AB = 13, BF = 9,and FC = 5.6, find each measure & the perimeter of triangle ABC.

harina [27]

Answer:

$Perimeter = 38.6$

Step-by-step explanation:

Given

$A\ B = 13$

$B\ F = 9$

$F\ C = 5.6$

Required

Calculate the perimeter of A B C

To calculate the perimeter of A B C, we sum up the sides of the triangle

i.e.

$Perimeter = A B + B\ C + A\ C$

AB is given in the question already.

So, we need to calculate B F and F C

To solve for BF, we consider triangle B F C

Using Pythagoras Theorem, we have:

$B\ C^2 = B\ F^2 + F\ C^2$

Substitute values for BF and FC;

$B\ C^2 = 9^2 + 5.6^2$

$B\ C^2 = 81 + 31.36$

$B\ C^2 = 112.36$

$B\ C^2= \sqrt{112.36$

$B\ C = 10.6$

Next, we calculate A C.

To calculate A C, we need to calculate A F, considering triangle B F A

Using Pythagoras Theorem, we have:

$A\ B^2 = B\ F^2 + A\ F^2$

Substitute values for B F and A B;

$13^2 = 9^2 + A\ F^2$

$169= 81 + A\ F^2$

$A\ F^2 = 169 - 81$

$A\ F^2 = 88$

$A\ F = \sqrt{88$

$A\ F = 9.4$

Since F lies on line A C:

$A\ C = A\ F + F\ C$

$A\ C = 9.4 + 5.6$

$A\ C = 15.0$

Recall that:

$Perimeter = A\ B + B\ C + A\ C$

$Perimeter = 13 + 10.6 + 15.0$

$Perimeter = 38.6$

<em>Hence, the perimeter is 38.6</em>

3 0

3 years ago