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Musya8 [376]
3 years ago
14

What is the solution to –2(5y – 5) – 3y ≤ –7y + 22?

Mathematics
2 answers:
Gre4nikov [31]3 years ago
6 0
-2(5y - 5) - 3y < = -7y + 22
-10y + 10 - 3y < = -7y + 22
-13y + 10 < = -7y + 22
-13y + 7y < = 22 - 10
-6y < = 12
y > = -12/6
y > = -2....answer B

slavikrds [6]3 years ago
4 0

Answer:

Option: B is the correct answer.

y≥ -2

Step-by-step explanation:

We are asked to find the solution of the inequality:

–2(5y – 5) – 3y ≤ –7y + 22.

We will solve for the inequality as:

-2×5y-2×(-5)-3y ≤ -7y+22   (on solving for the parantheses in the left hand side of the inequality)

-10y+10-3y ≤ -7y+22

⇒ -10y+7y-3y ≤ 22-10   (on combining the like terms)

⇒  -6y ≤  12

⇒  y≥ -2 (on dividing both side by -6 also the sign of the inequality changes as the negative sign is treated on both the side)

Hence option: B is the correct answer.

y ≥ -2.

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gtnhenbr [62]

Answer:

(x+y)(x-y)

x^2 - xy + xy - y^2

x^2 - y^2

7 0
2 years ago
2(1 − x) = 9(1 + 2x) + 52(1 − x) = 9(1 + 2x) + 5
marusya05 [52]

Solving the equation 2(1-x) = 9(1 + 2x) + 5 we get x=-\frac{3}{5}

Step-by-step explanation:

We need to solve the equation 2(1-x) = 9(1 + 2x) + 5 and find value of x

Solving:

2(1-x) = 9(1 + 2x) + 5\\2-2x=9+18x+5\\Adding\,\,-18x\,\,on\,\,both\,\,sides:\\2-2x-18x=9+5\\Adding\,\,-2\,\,on\,\,both\,\,sides\\-20x=14-2\\-20x=12\\x=\frac{12}{-20}\\x=-\frac{3}{5}

So, solving the equation 2(1-x) = 9(1 + 2x) + 5 we get x=-\frac{3}{5}

Keywords: Solving Equations

Learn more about Solving Equations at:

  • brainly.com/question/1563227
  • brainly.com/question/2403985
  • brainly.com/question/11229113

#learnwithBrainly

7 0
3 years ago
Lim x-1 x2 - 1/ sin(x-2)
balu736 [363]

Answer:

           \lim_{x \to 1}\frac{x^2-1}{sin(x-2)}=0

Explanation:

Assuming the correct expression is to find the following limit:

         \lim_{x \to 1}\frac{x^2-1}{sin(x-2)}

Use the property the limit of the quotient is the quotient of the limits:

         \lim_{x \to 1}\frac{x^2-1}{sin(x-2)}=\frac{\lim_{x \to 1}x^2-1}{\lim_{x \to 1}sin(x-2)}

Evaluate the numerator:

          \frac{\lim_{x \to 1}x^2-1}{\lim_{x \to 1}sin(x-2)}=\frac{1^2-1}{\lim_{x \to1}sin(x-2)}=\frac{0}{\lim_{x \to 1}sin(x-2}

Evaluate the denominator:

  • Since         \lim_{x \to1}sin(x-2)\neq 0

                  \frac{0}{\lim_{x \to1}sin(x-2)}=0

4 0
3 years ago
There are 30 students in the school chorale, and 12 of these students can stay after school today to help prepare the stage for
gtnhenbr [62]
Well it would be 12/30 but it could divide by 2 which equals 6/15 which can be divided by 3 which equals 2/5 so the answer 2/5
8 0
3 years ago
Please help I have 30 mins
Vladimir79 [104]

Answer:  0.6 in 10 % ; 0.4 in 15 %

Step-by-step explanation:

1. (x*10%) + (y*15%)/ x+y=12%

2. x+y = 1  x= 1-y

(0.1x + 0.15y/ x+y= 12/100) * 100

(10x + 15y/x+y = 12)*(x+y)

10x+15y= 12x + 12y

-2x=-3y

2x = 3y   2(1 - y)= 3y

2-2y=3y   2= 5y

y= 0.4

x= 0.6

4 0
3 years ago
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