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SCORPION-xisa [38]
3 years ago
11

For the function y=-3+4 cos(5pi/6(x+4)) what is the minimum value

Mathematics
2 answers:
Vikentia [17]3 years ago
5 0
Interval <-1;1>, which means that this function can take values from interval <-7;-1>. The minimum value is -7.
fomenos3 years ago
5 0

Answer:

the other guy is right, the answer is -7

Step-by-step explanation:

You might be interested in
Lines DE and AB intersect at point C.
alexandr402 [8]

Answer:

25

Step-by-step explanation:

2x+2+5x+3=180 (angles on a straight line)

7x+5=180

7x=180-5

7x=175

x=25 (dividing both sides by 7)

3 0
3 years ago
Choose the correct answer: 15 is 3% of<br> (A) 1.5<br> (B) 2.5<br> (C) 500 <br> (D) 5000
eduard

Answer:

c) 500

Step-by-step explanation:

3% = 0.03

multiply the decimal from of 3% by 500:

500 x 0.03

solve:

500 x 0.03 = 15

3 0
3 years ago
HIGH POINT REWARD
Yuki888 [10]
Total number of seniors = 55 + 70 = 125
Number of seniors who plan to go to college = 55

Percentage of seniors who plan to go to college = 55/125 x 100 = 44%

Answer: 44%
3 0
3 years ago
On day two of a study on body temperatures, 106 temperatures were taken. Suppose that we only have the first 10 temperatures to
NemiM [27]

Answer:

The 95% confidence interval for the mean of all body temperatures is between 97.76 ºF and 99.12 ºF

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 10 - 1 = 9

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 9 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 2.2622

The margin of error is:

M = T*s = 2.2622*0.3 = 0.68

In which s is the standard deviation of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 98.44 - 0.68 = 97.76 ºF

The upper end of the interval is the sample mean added to M. So it is 98.44 + 0.68 = 99.12 ºF

The 95% confidence interval for the mean of all body temperatures is between 97.76 ºF and 99.12 ºF

4 0
3 years ago
Help plzzzzzzzzzzzzzzzzzzzzz
Lady bird [3.3K]

Answer:

like what type of help that i could help u

5 0
3 years ago
Read 2 more answers
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