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Ad libitum [116K]
3 years ago
11

A road bike has a wheel diameter of 622 mm. What is the circumference of the wheel? Use 3.14 for mc015-1.jpg

Mathematics
2 answers:
Serga [27]3 years ago
7 0
Since the formula for circumference is pi*diameter, you multiply 3.14 by 622 mm to get 1953.08 mm as your circumference.
gtnhenbr [62]3 years ago
5 0

Answer: 1953.08 mm

Step-by-step explanation:

We know that circumference of a circle is given by ;-

\text{Circumference}=2\pi r, where r is the radius of the circle.

Given: the diameter of the wheel = 622 mm

Then, the radius of the wheel =\dfrac{622}{2}=311\ mm

Now, the circumference of the wheel is given by ;-

\text{Circumference}=2\pi (311)\\\\\Rightarrow\ \text{Circumference}=2(3.14)(311)\\\\\Rightarrow\ \text{Circumference}=1953.08\ mm

Hence, the circumference of the wheel = 1953.08 mm.

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3 years ago
The area of a rectangle is 42 m2, and the length is
MrRissso [65]

Answer:

length = 14 m

width = 7 m

Step-by-step explanation:

l = length

w = width

l = 2w - 8

w(2w - 8) = 42

2w² - 8w - 42 = 0

you can factor out a 2 to work with smaller numbers:

w² - 4w - 21 = 0

(w - 7)(w + 3) = 0

w = 7

'w' cannot equal a negative so we discount it as an answer

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l = 2(7) - 8

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6 0
3 years ago
How do I do this ? I need help
Amiraneli [1.4K]

Answer: 40

Step-by-step explanation:

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15 x 16 = 240

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240/6 is 40

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3 years ago
Ivan, a botanist, treated a 2 cm plant with a special growth fertilizer. With this fertilizer,
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Evaluate exactly the value of the integral from -1 to 0 (2x^4+8x)^3 (4x^3+4),dx. Include the use of substitution and the antider
ddd [48]
Hello,

Let's be

 z=2x^4+8x \\
dz=(8x^3+8)\ dx=8(x^3+1)\ dx \\

 \int\limits^0_{-1} {(2x^4+8x)^3*(4x^3+4)} \, dx =4* \int\limits^0_{-6} { \dfrac{z^3}{2}} \, dz \\
= 2* \left[\begin{array}{ccc} \dfrac{z^4}{4}\end{array}\right] ^0_{-6}=
\left[\begin{array}{ccc} \dfrac{z^4}{2}\end{array}\right] ^0_{-6}=0-648=-648

3 0
4 years ago
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