<img src="https://tex.z-dn.net/?f=8x%5E2%2B16x%2B8%20" id="TexFormula1" title="8x^2+16x+8 " alt="8x^2+16x+8 " align="absmiddle"

kow [346]

3 years ago

class="latex-formula">
Find the real/complex root of 8x^2+16+8

Mathematics

2 answers:

MrMuchimi3 years ago

6 0

I’m pretty sure it is -1 but I might be wrong so, correct me if I am

Dima020 [189]3 years ago

4 0

Answer:

real root =-1 (repeated)

Step-by-step explanation:

8x²+16x+8

8(x²+2x+1)

8(x+1)²=0

x=-1,-1

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