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Anestetic [448]
3 years ago
10

Need help solving this -3 + y = 0

Mathematics
2 answers:
Mrrafil [7]3 years ago
8 0
Fue answer is poseitive3
Andrews [41]3 years ago
7 0
The answer would be +3 because in order to get the equation to equal 0 the you would need to add 3 to -3
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Katena32 [7]
Your answer to this question is B
3 0
2 years ago
In this equation What is 77+23
kondaur [170]
The answer is 100 I’m sure
3 0
3 years ago
Read 2 more answers
Josh buys cucumbers that cost $0.62 per pound. He pays $2.79 for the cucumbers. How many pounds of cucumbers does Josh have?​
borishaifa [10]

Answer:

Josh bought 4.5 pounds of cucumbers.

Step-by-step explanation:

2.79 divided by the cost per pound, .62, is 4.5. Therefore he bought 4.5 pounds of cucumbers

6 0
3 years ago
) Evaluating a polynomial limit analytically You should have learned by now the process for finding the derivative of a polynomi
wolverine [178]

Answer:

This code or is program to find a given value of derivative of  a polynomial.

Step-by-step explanation:

We know already how to apply or make the procedures mathematically talking so this short program will eventually help you how to find logic.

// libraries

#include <stdio.h>

#include <conio.h>

//use to control floating elements

float poly(float a[], int, float);

//main

int main()

{

// Enter the degree of polynomial equation

float x, a[10], y1;

int deg, i;

printf("Enter the degree of polynomial equation: ");

scanf("%d", &deg);

printf("Ehter the value of x for which the equation is to be evaluated: ");

// Enter the coefficient of x to the power

scanf("%f", &x);

for(i=0; i<=deg; i++)

{

 printf("Enter the coefficient of x to the power %d: ",i);

 scanf("%f",&a[i]);

}

// The value of polynomial equation for the value of x

y1 = poly(a, deg, x);

 

printf("The value of polynomial equation for the value of x = %.2f is: %.2f",x,y1);

 

return 0;

}

/* function for finding the value of polynomial at some value of x */

float poly(float a[], int deg, float x)

{

float p;

int i;

 

p = a[deg];

 

for(i=deg;i>=1;i--)

{

 p = (a[i-1] + x*p);

}

 

return p;

}

8 0
2 years ago
Given that f(x) = 19x2 + 152, solve the equation f(x) = 0
telo118 [61]

<em><u>Option A</u></em>

<em><u>The solution is:</u></em>

x = \pm 2i \sqrt{2}

<em><u>Solution:</u></em>

f(x) = 19x^2+152

We have to solve the equation f(x) = 0

Let f(x) = 0

0=19x^2+152

Solve the above equation

19x^2 + 152 = 0

\mathrm{Subtract\:}152\mathrm{\:from\:both\:sides}\\\\19x^2+152-152=0-152\\\\Simplify\ the\ above\ equation\\\\19x^2 = -152\\\\\mathrm{Divide\:both\:sides\:by\:}19\\\\\frac{19x^2}{19} = \frac{-152}{19}\\\\x^2 = -8

Take square root on both sides

x =  \pm \sqrt{-8}\\\\x = \pm \sqrt{-1}\sqrt{8}\\\\\mathrm{Apply\:imaginary\:number\:rule}:\quad \sqrt{-1}=i\\\\x = \pm i\sqrt{8}\\\\x = \pm i \sqrt{2 \times 2 \times 2}\\\\x = \pm 2i\sqrt{2}

Thus the solution is found

5 0
3 years ago
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