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Arte-miy333 [17]
3 years ago
14

A certain relationship is defined as having only one corresponding y-value for each x-value. Which of the following best describ

es this relationship?
A.
variable
B.
function
C.
equation
D.
expression
Mathematics
1 answer:
Irina-Kira [14]3 years ago
4 0
The answer is b) function.

a function is special relationship where each input has a single output. it is often written as "f(x)" where x is the input value. hope this helped!
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If you were to make a line graph which two numbers would be 3.275 be in between if you are trying to round it to the nearest who
alina1380 [7]
Whole number would be 3, so the middle would be 1.5
Nearest tenth would be 3.3, so the middle would be 1.65
Nearest hundredth would be 3.28, so the middle would be 1.64
(I'm not sure if that's what you meant)
5 0
3 years ago
Someone please answer my question please I am struggling and need to finish tonight I think I got the answer but I am not sure p
NeX [460]

In the figure we have three right angles .The triangles similar to each other .Similar triangles have sides in proportion .The altitude rule is true for the triangles .

The theorem states :The altitude to the hypotenuse of a right triangle is the mean proportional between the segments into which it divides the hypotenuse.

\frac{part of hypotenuse}{altitude} =\frac{altitude}{other part hypotenuse }

Substituting the values from the triangles we ahve:

\frac{r}{h} =\frac{h}{s}

s is the right answer

4 0
4 years ago
What is the solution of log 3(x - 2)125 = 3 ? Choose one answer. a. x = 1 over 3 b. x = 1 c. x = 7 over 3 d. x = 4
SVETLANKA909090 [29]
From the definition of logarithm:
log_b x = y if b^y = x (1)

The equation in our problem is:
log_{3x-2} 125 = 3
If we use definition (1), this equation becomes
(3x-2)^3 = 125

Let's solve it:
(3x-2)^3 = 5^3
3x-2 = 5
3x=7
x= \frac{7}{3}

therefore, the correct answer is C).
3 0
4 years ago
F(x) = 4^ x / 8<br><br> can you Graph this ?
k0ka [10]

Answer:

Graph is below

Brainliest, please :)

5 0
2 years ago
Identify the best big-O estimate for the number of comparisons used by the algorithm that determines the number of 1s in a bit s
Westkost [7]

Answer:

0(n)

Step-by-step explanation:

Result previous exercise:  

procedure count(a1a2...an : string with n > 1)

i:=0

for k:=1 to n

if ak =1 then i:=i + I

return i  

<em>Note</em><em>: If you use a different algorithm, then you could possible get different results.  </em>

<u>SOLUTION  </u>

There is only one part of the code that contains an operation (comparison), namely if a_k =1  

This comparison is executed in every iteration of the for-loop  

k can take on the values from 1 to n (for k:=I to n), thus k can take on n values.  

Thus in total there are then n comparisons, while n is 0(n).

5 0
3 years ago
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