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ollegr [7]
4 years ago
11

A research company wants to test the claim that a new multi vitamin helps improve short term memory state the objective of the e

xperiment suggest a population determine the experimental and control groups and describe a simple procedure
Mathematics
1 answer:
Vsevolod [243]4 years ago
8 0

Answer:

To test the effects of the multi-vitamin, we must test it on people with short-term memory loss. So the population should be people with short-term memory loss. The independent variable is the multi-vitamin and the dependent variable is the short term memory state of the people being tested. A control group can consist of people with short-term memory loss NOT being treated by the multi-vitamin.

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What is the SLOPE and Y-INTERCEPT of the following equation. y = -x +7 ​
Natalka [10]
The slope is m=-1
Because the formula is y=mx+b (b is the intercept) (or replace 0 with x so that will be y=7)
And the Y intercept is 7 :)
I hope this helped!
8 0
3 years ago
Solve the inequality for x<br><br> 19&gt;x-5<br><br> Simplify your answer as much as possible.
Stolb23 [73]
19>x-5

Add 5 on each side giving you
19+5>x
24>x

x<24

Hope this helps!!
7 0
4 years ago
A chain lying on the ground is 10 m long and its mass is 70 kg. How much work (in J) is required to raise one end of the chain t
DerKrebs [107]

Answer:

W= 34.3 \frac{kg}{s^2} (4^2-0^2)m^2 =548.8 \frac{kg m^2}{s^2} =548.8 J

Step-by-step explanation:

Data Given: m = 70 kg , g = 9.8 ms^-2, h =10m.

For this case we can use the following formula:

W = \int_{x_i}^{x_f} F(x) dx

For this case we need to find an expression for the force in terms of the distance. And since on this case the total distance is 10 m long we can write the expression like this:

F(x) = \frac{ma}{10m}= \frac{mg}{10m} x

The only acceleration on this case is the gravity and if we replace the values given we got:

\frac{70 kg *9.8 m/s^2}{10m} x=68.6 x\frac{kg}{s^2}

Now we can find the required work with the following integral:

W= 68.6 \frac{kg}{s^2} \int_{0}^4 x dx

W= 34.3 \frac{kg}{s^2} x^2 \Big|_0^4

W= 34.3 \frac{kg}{s^2} (4^2-0^2)m^2 =548.8 \frac{kg m^2}{s^2} =548.8 J

7 0
4 years ago
0.06 is 10 times as great as
Butoxors [25]
0.006 is your answer.......
3 0
4 years ago
Please help it’s so difficult
Sergeu [11.5K]

Answer:

y = x/2 +4

Step-by-step explanation:

new slope = -1/-2 = 1/2

x1 = -4, y1= 2

y-y1 = m(x-x1)

y - 2 = 1/2 {x- (-4)}

y-2 = 1/2 (x+4)

y-2 = x/2 + 2

y = x/2 +2+2

y = x/2 +4

3 0
3 years ago
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