what is the probability of drawing two blue cards if the first card is not included in the second draw? simplify your answer com
pletely
1 answer:
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Answer:
(a)
(b)
(i)probability that the product of the two numbers is a prime number=7/64
(ii)probability that the product of the two numbers is not a perfect square=56/64
(iii)probability that the product of the two numbers is a multiple of 5 =15/64
(iv)probability that the product of the two numbers is Less than or equal to 21 =40/64
(v) probability that the product of the two numbers is divisible by 4 or 6 =42/64
Step-by-step explanation:
(a) 8-sided fair die implies each die can have outcomes 1,2,3,4,5.6,7,8 with equal chances.
To draw the possibility diagram of the product of the two numbers appearing on the die in each throw, we put the outcomes of both dies side by side and find the product of possible outcomes.
(b) probability= Number of outcome / Total number of outcomes
(i)probability that the product of the two numbers is a prime number=8/64=1/8
based on sample space, the prime numbers are 2,2,3,3,5,5,7,7
(ii)probability that the product of the two numbers is not a perfect square=56/64=7/8
based on sample space, only 1,4,9,16,25,36,49,64 are perfect square
(iii)probability that the product of the two numbers is a multiple of 5 =15/64
(iv)probability that the product of the two numbers is Less than or equal to 21 =40/64=5/8
(v) probability that the product of the two numbers is divisible by 4 or 6 =42/64=21/32