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3 years ago

Pizza help I will give brainliest!!

Mathematics

1 answer:

Inga [223]3 years ago

4 0

Answer:

The answer is A.

Step-by-step explanation:

The answer is A because you are working at a constant rate on the necklace without taking a break. Because you are working at a constant rate, the line on the graph will keep rising without stopping.

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The graph shows the scores of an exam. About what percent of students scored above 86%?

Gemiola [76]

Attach shows the scores of students in an exam

$\begin{gathered} \text{(students scored above 86\%) = }\frac{\text{ number of students score above 86\%}}{\text{Total scored }}\text{ x }\frac{100}{1} \\ \text{(students scored above 86\%) = }\frac{\text{8+5.9+2.2+2}}{1.4+2.2+4.5+6.2+8.5+16.5+18+16.3+8+8+5.9+2.2+2}X\frac{100}{1} \\ \\ \text{(students scored above 86\%) = }\frac{18.1}{99.7}\text{ X }\frac{100}{1} \\ \text{(students scored above 86\%) = }18.15\text{ \%} \\ \text{(students scored above 86\%) = 18\%} \end{gathered}$

Hence the correct answer = 18% Option A

8 0

1 year ago

Express the fifth roots of unity in standard form a + bi. with 1 + 0i

marishachu [46]

Answer:

For K=0

$cos(\frac{0+2\pi 0}{5})+isin(\frac{0+2\pi 0}{5})\\cos(0)+isin(0)=1+i0$

For K=1:

$cos(\frac{0+2\pi 1}{5})+isin(\frac{0+2\pi 1}{5})\\cos(2\pi/5)+isin(2\pi/5)=0.3090+i0.9510$

For K=2:

$cos(\frac{0+2\pi 2}{5} )+isin(\frac{0+2\pi 2}{5} )\\cos(4\pi/5)+isin(4\pi/5)=-0.809+i0.587$

For K=3:

$cos(\frac{0+2\pi 3}{5} )+isin(\frac{0+2\pi 3}{5} )\\cos(6\pi/5)+isin(6\pi/5)=-0.809-i0.587$

For K=4:

$cos(\frac{0+2\pi 4}{5} )+isin(\frac{0+2\pi 4}{5} )\\cos(8\pi/5)+isin(8\pi/5)=0.3091-i0.9510$

Step-by-step explanation:

Fifth Root is given by:

$\sqrt[5]{z}=1+0i$

The above equation will become:

$z=(1+0i)^5$

It can be written as:

$z=[cos(0)+isin(0)]^5$

|z|=1,

According to De-moivre's Theorem:

$z=cos(\frac{0}{5})+isin(\frac{0}{5})\\ z=cos(0)+isin(0)$

Now, Fifth Roots of unity in standard form a + bi :

$\sqrt[5]{z}=[{cos(0+2\pi k)+isin(0+2\pi k)}]^{1/5}$

k=0,1,2,3,4

For K=0

$cos(\frac{0+2\pi 0}{5})+isin(\frac{0+2\pi 0}{5})\\cos(0)+isin(0)=1+i0$

For K=1:

$cos(\frac{0+2\pi 1}{5})+isin(\frac{0+2\pi 1}{5})\\cos(2\pi/5)+isin(2\pi/5)=0.3090+i0.9510$

For K=2:

$cos(\frac{0+2\pi 2}{5} )+isin(\frac{0+2\pi 2}{5} )\\cos(4\pi/5)+isin(4\pi/5)=-0.809+i0.587$

For K=3:

$cos(\frac{0+2\pi 3}{5} )+isin(\frac{0+2\pi 3}{5} )\\cos(6\pi/5)+isin(6\pi/5)=-0.809-i0.587$

For K=4:

$cos(\frac{0+2\pi 4}{5} )+isin(\frac{0+2\pi 4}{5} )\\cos(8\pi/5)+isin(8\pi/5)=0.3091-i0.9510$

6 0

3 years ago

Write 1/32 as a power of 2

Aleksandr [31]

<span> 32=2^5

^ = "to the power of"

1/32=1/2^5

1/2^5=2^-5

so

1/32=2^-5 </span>

3 0

3 years ago

Read 2 more answers

The resistance, R, to electricity of a cylindrical-shaped wire is given by the equation R=pL/(pi)d^2 where p represents the resi

SashulF [63]

Answer:

The resistance approaches infinity

Step-by-step explanation:

We are given

The resistance, R, to electricity of a cylindrical-shaped wire is given by the equation

$R=\frac{\rho L}{\pi (d)^2}$

where

p represents the resistivity of the wire’s material

L represents the length of the wire

d represents the diameter of the wire

now,

d approaches to 0

so, we can plug d=0 and find R

$R=\frac{\rho L}{\pi (0)^2}$

$R=\frac{\rho L}{0}$

$R=\infty$

So,

The resistance approaches infinity

6 0

4 years ago

Read 2 more answers

Which expression can be used to find the slope of a line containing the points (-3,2) and (7,-1)

Ket [755]

The right expression is -1-2/7-(-3) which then gives you -3/10

4 0

3 years ago

Read 2 more answers

Pizza help I will give brainliest!!​

Pizza help I will give brainliest!!