Answer: H
Step-by-step explanation:
So this is called a problem you would use PEMDAS or (please-excuse-my-dear-aunt-sally)
Parenthesis
Exponents
Multiply
Divide
Addition
Subtract
In this sens, since parenthesis are present you do them first so it would be H
24/4=6
so 6 pieces on each side, since a rectangle is a square
Answer:
0.1937984496 lbs
Step-by-step explanation:
10 ÷ 516
<h3>
Answer: Choice D</h3><h3>
m = n</h3><h3>
b = sqrt(pi)*a</h3>
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Explanation:
Each circle has a radius of 'a'. So r = a.
The area of each circle is pi*r^2 = pi*a^2
The area of each square with side length b is b^2
The two stacks have the same volume only when the circle area is equal to the square area, so whenever pi*a^2 = b^2 is true.
Solving for b leads to b = sqrt(pi*a^2) = sqrt(pi)*a
The stacks must also be the same height for the volumes to be the same, so m = n as well.
IQR = 40
1) Put the numbers in order: 40, 45, 50, 60, 60, 75, 90, 90, 120
2) Find the median: Median is 60 (the 2nd one)
3) Place parentheses around the numbers above and below the median. For easy identification of Q1 and Q3. (40, 45, 50, 60,) 60, (75, 90, 90, 120)
4) Find the Q1 and Q3. Q1 = median of the lower half of the data; Q3 = median of the higher half of the data. Q1 and Q3 have even sets so its median cannot be defined.
5) Had both sets contain odd sets, the median of Q1 is subtracted from the median of Q3 to get the IQR.
We can then use the Alternative definition of IQR.
IQR is the difference between the largest and smallest values in the middle 50% of a set data.
40, 45, 50, 60, 60, 75, 90, 90, 120
Middle 50% is 50, 60, 60, 75, 90; IQR = Largest value - smallest value;
IQR = 90 - 50 = 40
