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katrin [286]
3 years ago
8

787.4÷127 show the work

Mathematics
2 answers:
wolverine [178]3 years ago
7 0
Use photo math or Socratic. It shows you how they got the answer.

neonofarm [45]3 years ago
5 0
I hope this helps! When dividing a number with a decimal you can move the decimal to the end and solve.

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What is the volume of a cylinder, in cubic inches, with a height of 2 inches and a base diameter of 18 inches? Round to the near
QveST [7]

Answer:

V≈508.94in³

Step-by-step explanation:

V≈508.94in³ nearest 10th will be 510 in3

8 0
3 years ago
Rachel loves to bake cookies, but she has an old oven that has trouble maintaining a constant temperature. Assume the acceptable
denis-greek [22]

Answer:

3.00

Step-by-step explanation:

USL = 350+18 = 368

z = (USL-Mean)/6*σ = (368-350)/6*σ

σ = 3/0.9999966 = 3.00 (approx)

7 0
3 years ago
On the first of each month, Shelly runs a 5k race. She keeps track of her times to track her progress. Her time in minutes is re
Vikki [24]

Answer:

C . 0.76

Step-by-step explanation:

We are given that on the first of each month , Shelly runs a 5 k race. She keeps track of her times to track her progress. Her time in minutes is recorded in the table:

Jan  40.55 Feb 41.51

March 42.01 Apr 38.76

May 36.32  June 34.28

July 35.38  Aug 37.48

Sept 40.87 Oct 48.32

Nov 41.59 Dec 42.71

We have to find the difference between the mean of the data , including the outlier and excluding the outlier

Outlier: That observation which is different from other observations.

The outlier in the given observations is 48.32 because is different from other observations.

Mean of the data including the outlier

Mean =\frac{Sum \;of\;observations}{Total\;number\;of\;observations}

Mean=\frac{40.55+41.51+42.01+38.76+36.32+34.28+35.38+37.48+40.87+48.32+41.59+42.71}{12}

Mean=\frac{479.78}{12}

Mean=39.982

Mean of the data excluding the outlier

Mean=\frac{40.55+41.51+42.01+38.76+36.32+34.28+35.38+37.48+40.87+41.59+42.71}{11}Mean=[tex]\frac{431.46}{11}

Mean=39.224

Difference between mean of the data including the outlier and excluding the outlier=39.982-39.224=0.758

Difference between mean of the data including the outlier and excluding the outlier=0.76

Answer Answer:

Step-by-step explanation:

We are given that on the first of each month , Shelly runs a 5 k race. She keeps track of her times to track her progress. Her time in minutes is recorded in the table:

Jan  40.55 Feb 41.51

March 42.01 Apr 38.76

May 36.32  June 34.28

July 35.38  Aug 37.48

Sept 40.87 Oct 48.32

Nov 41.59 Dec 42.71

We have to find the difference between the mean of the data , including the outlier and excluding the outlier

Outlier: That observation which is different from other observations.

The outlier in the given observations is 48.32 because is different from other observations.

Mean of the data including the outlier

Mean =\frac{Sum \;of\;observations}{Total\;number\;of\;observations}

Mean=\frac{40.55+41.51+42.01+38.76+36.32+34.28+35.38+37.48+40.87+48.32+41.59+42.71}{12}

Mean=\frac{479.78}{12}

Mean=39.982

Mean of the data excluding the outlier

Mean=\frac{40.55+41.51+42.01+38.76+36.32+34.28+35.38+37.48+40.87+41.59+42.71}{11}Mean=[tex]\frac{431.46}{11}

Mean=39.224

Difference between mean of the data including the outlier and excluding the outlier=39.982-39.224=0.758

Difference between mean of the data including the outlier and excluding the outlier=0.76

Answer :C . 0.76

5 0
3 years ago
Read 2 more answers
Please help i reward brainliest and give points
Ostrovityanka [42]
What is the question?
5 0
2 years ago
Help picture below problem 23
strojnjashka [21]

Answer: 7 hours.

Step-by-step explanation: Randall can assemble 5 race car tracks in an hour and Diggery can assemble 4 race car tracks in an hour.  To see how many hours it takes to make 63 race car tracks, you need to add 5 and 4, since Randall and Diggery are working together.  Both of them combined can make 9 race car tracks in total every hour.  63 can be divided by 9, which is 7.  Therefore, it'll take 7 hours for both of them to make 63 race car tracks.

Let me know if this is right! :)

7 0
2 years ago
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