We will investigate how to determine Hamilton paths and circuits
Hamilton path: A path that connect each vertex/point once without repetition of a point/vertex. However, the starting and ending point/vertex can be different.
Hamilton circuit: A path that connect each vertex/point once without repetition of a point/vertex. However, the starting and ending point/vertex must be the same!
As the starting point we can choose any of the points. We will choose point ( F ) and trace a path as follows:
The above path covers all the vertices/points with the starting and ending point/vertex to be ( F ). Such a path is called a Hamilton circuit per definition.
We will choose a different point now. Lets choose ( E ) as our starting point and trace the path as follows:
The above path covers all the vertices/points with the starting and ending point/vertex are different with be ( E ) and ( C ), respectively. Such a path is called a Hamilton path per definition.
One more thing to note is that all Hamilton circuits can be converted into a Hamilton path like follows:
The above path is a hamilton path that can be formed from the Hamilton circuit example.
But its not necessary for all Hamilton paths to form a Hamilton circuit! Unfortunately, this is not the case in the network given. Every point is in a closed loop i.e there is no loose end/vertex that is not connected by any other vertex.
More likely because you are doing a job that you enjoy doing.
(10 + a / 2, 2 + b / 2) = (8, 1)
10 + a / 2 = 8
10 + a = 16
a = 6
2 + b / 2 = 1
2 + b = 2
b = 0
so V(6, 0)
Answer:
(x–1)(x²–6x+6)
Explanation:
Given that 1 is a zero, we can use synthetic division to compute the factor.
If 1 is a zero (x–1) is a factor.
Here is the process:
| 1 | 1 -7 12 -6
↓ +(1) +(-6) +(6)
↓ ↓ ↓
1 -6 6 0
→ [1]x² + [-6]x + [6]1 + [0]/x–1 =
x² – 6x + 6.
Therefore the factors are (x–1)(<u>x²–6x+6</u>)