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jok3333 [9.3K]
3 years ago
15

James is fencing off a triangular region for his cats to play in. From the first fence post, he walks 13 meters in a straight li

ne and plants the second fence post. From there, James heads in another direction for 5 meters and places the third fence post. If the distance between the first and third fence posts is 9 meters, find the area of the enclosed region. Round the answer to the nearest tenth.
Mathematics
1 answer:
GenaCL600 [577]3 years ago
4 0
You can use Heron's formula to do this  

Area of triangle = sqrt[ s(s-a)(s-b)(s-c) ]   where s = half the perimeter of the triangle = 
1/2 * 13+5+9 = 13.5
so required area =  sqrt [ (13.5)(13.5-13)(13.5-5)(13.5-9)]
                            =  16.1  square meters
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The problem solved correctly as a single logarithm is log_{a} 2x^{3}/y^{2}

<h3>Simplifying Logarithm</h3>

From the question, we are to simplify the given logarithm

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2 years ago
Mike and Ike are twins. Mike’s age is one more than twice a certain number. Ike’s age is 10 less than triple that same number. F
Misha Larkins [42]
Mike age is 3 less then twice the age of his brother nuke.
M = Mike's age now
N = Nuke's age now
M = 2N - 3

Ten years ago, four times nuke's age was one more mike's age.
M-10 = Mike's age 10 years ago
N-10 = Muke's age 10 years ago
4(N - 10) = 1 + M -10

what are their present ages

find M and N

substitute M = 2N - 3 into 4(N - 10) = 1 + M -10:

4(N - 10) = 1 + [2N - 3] - 10
4N - 40 = 2N - 12
2N = 28
N = 14

M = 2(14) - 3 = 28 - 3 = 25

Mike is 25 and Nuke is 14.

check:
4(14 - 10) = 4(4) = 16 = 26 -10 = 1 + 25 - 10
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