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Pavlova-9 [17]
3 years ago
7

How do you solve for n^3 + 3n^2 + n - 33 = 0?

Mathematics
1 answer:
Inga [223]3 years ago
4 0

Answer:

  one real root: n ≈ 2.38450287889

Step-by-step explanation:

My favorite solution method for higher-degree polynomials is to use a graphing calculator.

Descartes' rule of signs tells you the one sign change among coefficients means there will be one positive real root. A graph shows you it is about 2.4, hence irrational (not a divisor of 33, so not rational).

You can use a cubic formula to find an explicit expression for the root, or you can find its value using any of several iteration methods. The attachment shows Newton's method iteration being used to refine the graph value of 2.385 to the more accurate 2.38450287889.

__

Factoring that root from the cubic results in a quadratic with irrational coefficients. Its vertex form is approximately ...

  y = (n +2.692)² + 6.591

Hence, the complex roots will be near -2.692±i√6.591.

_____

There are formulas for the roots of a cubic. The formula tells you the real root for this cubic is ...

  n = 2√(2/3)cosh(1/3·arccosh(24√(3/2))) -1 ≈ 2.38450287889

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Find the maclaurin series for the function. (use the table of power series for elementary functions.) f(x) = (cos(x 6))2
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F'<span>(x)</span>=−2<span>cos<span>(x)</span></span><span>sin<span>(x)</span></span> , <span><span>f''<span>(x)</span>=2<span><span>sin2</span><span>(x)</span></span>−2<span><span>cos2</span><span>(x)</span></span></span> </span>

<span><span>f'''<span>(x)</span>=4<span>sin<span>(x)</span></span><span>cos<span>(x)</span></span>+4<span>cos<span>(x)</span></span><span>sin<span>(x)</span></span>=8<span>cos<span>(x)</span></span><span>sin<span>(x)</span></span></span> </span>

<span><span>f''''<span>(x)</span>=−8<span><span>sin2</span><span>(x)</span></span>+8<span><span>cos2</span><span>(x)</span></span></span> </span>, <span><span>f'''''<span>(x)</span>=⋯=−32<span>cos<span>(x)</span></span><span>sin<span>(x)</span></span></span> </span>,

<span><span>f''''''<span>(x)</span>=32<span><span>sin2</span><span>(x)</span></span>−32<span><span>cos2</span><span>(x)</span></span></span> </span>, etc...

Hence, <span><span><span>f<span>(0)</span></span>=1</span> </span>, <span><span>f'<span>(0)</span>=0</span> </span>, <span><span>f''<span>(0)</span>=−2</span> </span>, <span><span>f'''<span>(0)</span>=0</span> </span>, <span><span>f''''<span>(0)</span>=8</span> </span>, <span><span>f'''''<span>(0)</span>=0</span> </span>, <span><span>f''''''<span>(0)</span>=−32</span> </span>, etc...

Since <span><span>2!=2</span> </span>, <span><span><span>8<span>4!</span></span>=<span>824</span>=<span>13</span></span> </span>, and <span><span><span><span>−32</span><span>6!</span></span>=<span><span>−32</span>720</span>=−<span>245</span></span> </span>, this much calculation leads to an answer of

<span><span>1−<span>x2</span>+<span><span>x4</span>3</span>−<span>245</span><span>x6</span>+⋯</span> </span>

This does happen to converge for all <span>x </span> and it does happen to equal <span><span><span>cos2</span><span>(x)</span></span> </span> for all <span>x </span>. You can also check on your own that the next non-zero term is <span><span>+<span><span>x8</span>315</span></span> </span>

2) Use the well-known Maclaurin series <span><span><span>cos<span>(x)</span></span>=1−<span><span>x2</span><span>2!</span></span>+<span><span>x4</span><span>4!</span></span>−<span><span>x6</span><span>6!</span></span>+⋯</span> </span>

<span><span>=1−<span><span>x2</span>2</span>+<span><span>x4</span>24</span>−<span><span>x6</span>720</span>+⋯</span> </span> and multiply it by itself (square it).

To do this, first multiply the first term <span>1 </span> by everything in the series to get

<span><span><span><span>cos2</span><span>(x)</span></span>=<span>(1−<span><span>x2</span>2</span>+<span><span>x4</span>24</span>−<span><span>x6</span>720</span>+⋯)</span>+⋯</span> </span>

Next, multiply <span><span>−<span><span>x2</span>2</span></span> </span> by everything in the series to get

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Then multiply <span><span><span>x4</span>24</span> </span> by everything in the series to get

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etc...

If you go out far enough and combine "like-terms", using the facts, for instance, that <span><span>−<span>12</span>−<span>12</span>=−1</span> </span> and <span><span><span>124</span>+<span>14</span>+<span>124</span>=<span>824</span>=<span>13</span></span> </span>, etc..., you'll eventually come to the same answer as above:

<span>1−<span>x2</span>+<span><span>x4</span>3</span>−<span>245</span><span>x6</span>+<span>⋯</span></span>

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