Question

Aiden's borrows a book from a public library.He read a few pages on day one.On day two,he reads twice the number of pages than he read on day one.On the third day,he reads six pages less than what he read on the first day.If he has read the entire book that contains 458 pages,how many pages did he read on day three?

Answer 1

Answer:

Aiden has read 110 pages on day three.

Step-by-step explanation:

Given:

Number of pages he read = 458

Let the number of pages read on Day 1 be $'x'$.

Also Given:

On day two,he reads twice the number of pages than he read on day one.

so we can say that;

Number of pages read on Day 2 = $2x$

Now Given:

On the third day,he reads six pages less than what he read on the first day.

so we say that;

Number of pages read on Day 3 = $x-6$

we need to find the Number of pages read on Day 3.

Now we know that;

Total number of pages he read is equal to sum of number of pages read on Day 1, Number of pages read on Day 2 and Number of pages read on Day 3.

framing in equation form we get;

$x+2x+x-6=458\\\\4x-6=458$

Adding both side by 6 using Addition property we get;

$4x-6+6=458+6\\\\4x=464$

Now By Using Division property we will divide both side by 4 we get;

$\frac{4x}{4}=\frac{464}{4}\\\\x=116 \ pages$

Number of pages read on 1 day = 116 pages.

Number of pages read on Day 3 = $x-6 =116-6 =110\ pages$

Hence Aiden has read 110 pages on day three.