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Citrus2011 [14]
3 years ago
8

For complex numbers z, let [tex] \[f(z) = \left\{

Mathematics
1 answer:
Nina [5.8K]3 years ago
6 0

f(i)+f(1)+f(-1)+f(-i)=i^2+1+2+(-1)+2+(-i)^2=-1+3-1+2-1=2

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A box contains 35 gems, of which 10 are real diamonds and 25 are fake diamonds. Gems are randomly taken out of the box, one at a
Sonja [21]

Answer:

Step-by-step explanation:

The total number of ways of selecting 3 gems of any kind without replacement is 35 * 34 * 33 = 39270

Now selecting 2 gems from 25 is 25C2

25 C 2 = 25 * 24/2 = 300

Selecting one good gem is 10

Total selection = 300 * 10 = 3000

P(gems) = 3000 / 39270

P(gems) = 300/3927

P(gems) = 100/1309

6 0
2 years ago
Help?<br><br> 3. Three times a number is two times the difference of that number and one.
erastovalidia [21]

Answer:

3x = 2(-3x + 1)

Step-by-step explanation:

I think that's it I think it could be wrong but I tried

8 0
3 years ago
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Mark runs 3/4 of a mile each day for 5 days. What is the total distance that Mark has run after 5 days? A.3 3/4 B.4 1/4 C.5 3/4
Evgen [1.6K]
3/4 x 5 = 3 3/4

Your answer is A.
6 0
3 years ago
pls There are (4^9)^5 ⋅ 4^0 books at the library. What is the total number of books at the library? A.4^9 B. 4^45 C. 4^46 D. 1  
jekas [21]
We know that there are (4^9)^5 ⋅ 4^0 at the library, so we just need to simplify this to get the answer.
(4^9)^5 ⋅ 4^0
=(4^9)^5×1
=(4^9)^5
=4^9×5
=4^45. As a result, the total number of books at the library is 4^45 books at the library or B is the final answer. Hope it help!
6 0
3 years ago
(4k^5-9k^4+k^3-7k^2-9k+28)/4k-5
vlada-n [284]

Answer:

=k6+ −9 /4  k5+ 1 /4  k4+  −7 /4  k3+  −9 /4  k2+7k−5

Step-by-step explanation:

7 0
3 years ago
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