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luda_lava [24]
3 years ago
8

What times what equals 152

Mathematics
1 answer:
erik [133]3 years ago
7 0

x*x=152


x2=152

Take square root.

x=±√152

x=√238
or
x=−√238

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(y=2x^2-7x+6)'          Differentiate the equation.

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Point slope form of a line is:

y-y_1=m(x-x_1)

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y-10=9(x-4)

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------------Formal Definition of Derivative----------------

The following limit will give us the derivative of the function f(x)=2x^2-7x+6 at x=4 (the slope of the tangent line at x=4):

\lim_{x \rightarrow 4}\frac{f(x)-f(4)}{x-4}

\lim_{x \rightarrow 4}\frac{2x^2-7x+6-10}{x-4}  We are given f(4)=10.

\lim_{x \rightarrow 4}\frac{2x^2-7x-4}{x-4}

Let's see if we can factor the top so we can cancel a pair of common factors from top and bottom to get rid of the x-4 on bottom:

2x^2-7x-4=(x-4)(2x+1)

Let's check this with FOIL:

First: x(2x)=2x^2

Outer: x(1)=x

Inner: (-4)(2x)=-8x

Last: -4(1)=-4

---------------------------------Add!

2x^2-7x-4

So the numerator and the denominator do contain a common factor.

This means we have this so far in the simplifying of the above limit:

\lim_{x \rightarrow 4}\frac{2x^2-7x-4}{x-4}

\lim_{x \rightarrow 4}\frac{(x-4)(2x+1)}{x-4}

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Now we get to replace x with 4 since we have no division by 0 to worry about:

2(4)+1=8+1=9.

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