∑ 4 * 5^(i-1) = 4 + 20 + 100 + 500 = 624
∑ 3 * 4^(i-1) = 3 + 12 + 48 + 192 + 768 = 1,023
∑ 5* 6^(i-1) = 5 + 30 = 35
∑ 5^(i-1) = 1 + 5 + 25 + 125 = 156
Answer:
∑ (i=1, 2) 5 * 6^(i-1) < ∑ (i=1, 4) 5^(i-1) < ∑ (i=1, 4) 4 * 5^(i-1) <
< ∑ (i=1, 5) 3 * 4^(i-1)
For there to be 1 car, we consider two possible outcomes:
The first door opened has a car or the second door opened has a car.
P(1 car) = 2/6 x 4/5 + 4/6 x 2/5
P(1 car) = 8/15
For there to be no car in either door
P(no car) = 4/6 x 3/5
P(no car) = 2/5
Probability of at least one car is the sum of the probability of one car and probability of two cars:
P(2 cars) = 2/6 x 1/5
= 1/15
P(1 car) + P(2 cars) = 8/15 + 1/15
= 3/5
Answer:
Relative frequencies
First row
0.8125 ,0.1875 ,16
Second row
0.555 ,0.444 ,9
third row
18 , 7 , 25
Step-by-step explanation:
Given data
allowance No allowance total
Chores 13 3 16
<u>No chores 5 4 9</u>
<u>Total 18 7 25</u>
<u><em>Relative frequencies</em></u>
allowance No allowance total
Chores 
16
No chores 
9
Total <u> 18 7 25</u>
For this case we model the problem as a rectangle.
The area of the rectangle is given by:
A = (w) * (l)
Where,
w: width
l: long
Substituting values we have:
4800 = (w) * ((1 1/3) * w)
We rewrite:
w ^ 2 = 4800 / (1 1/3)
w ^ 2 = 3600
w = root (3600)
w = 60 in
The long will be then:
l = (1 1/3) * w
l = (1 1/3) * (60)
l = 80 in
Answer:
the dimensions of the quilt are:
w = 60 in
l = 80 in
Sal: −38 feet
Sam: −45 feet
