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MariettaO [177]

2 years ago

8

(2x²ⁿ₊3x²ⁿ⁻¹)(x¹⁻²ⁿ₋3x²⁻²ⁿ)

1 answer:

Tcecarenko [31]2 years ago

8 0

Answer:

2x²ⁿ₊3x²ⁿ⁻¹)(x¹⁻²ⁿ₋3x²⁻²ⁿ)

Step-by-step explanation:

2x²ⁿ₊3x²ⁿ⁻¹)(x¹⁻²ⁿ₋3x²⁻²ⁿ)

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