Answer:1234567890
Step-by-step explanation:101112131415161789995657
Age of Jen is 13.6 years old
<em><u>Solution:</u></em>
Let "x" be the age of Jack and "y" be the age of Jen
Given that This Christmas, your brother Jack will be 2 years from being twice as old as your sister Jen
The above sentence can be written mathematically as:
Jack age + 2 = twice of age of Jen

The sum of Jacks age and three times Jen's age is 66
Jack age + three times Jen age = 66
x + 3y = 66 ---- eqn 2
Substitute eqn 1 in eqn 2
2y - 2 + 3y = 66
5y - 2 = 66
5y = 68
<h3>y = 13.6</h3>
Thus age of Jen is 13.6 years old
Exponent rule : (a^b)^c = a^(b*c)
31. (x^2)^3 = x^(2 * 3) = x^6
32. (a^7)^5 = a^(7 * 5) = a^35
33. (y^13)^4 = y^(13 * 4) = y^52
34. (w^-21)^-15 = w^(-21*-15) = w^315
35. (5^2)^3 = 5^(2 * 3) = 5^6
36. (23^7)^8 = 23^(7 * 8) = 23^56
37. (-y^5)^4 = -y^(5 * 4) = y^20
38. (4y^3)^2 = 4^2 y^(3 * 2) = 16y^6
39. (8c^5)^2 = 8^2 c^(5 * 2) = 64c^10
40. (-3h^9)^2 = -3^2 h^(9 * 2) = 9h^18
41. (y^4d^6)^3 = y^(4 * 3)d^(6 * 3) = y^12d^18
42. (-15h^9k^7)^3 = -15^3h^(9*3)k^(7*3) = -3375h^27k^21
43. (k^9)^5(k^3)^2 = k(9 * 5)k^(3 * 2) = (k^45)(k^6) = k^51
44. (3y^6)^2 (x^5y^2z) = 3^2y^(6*2)(x^5y^2z) = 9y^12(x^5y^2z) =
9x^5y^14z
45. (4h^3)^2 (-2g^3h)^3 = 4^2h^(3*2) (-2^3g^(3*3)h^3) = 16h^6(-8g^9h^3)
= -128g^9h^9
46. (14a^4b^6)^2 (a^6c^3)^2 = 14^2a^(4*2)b^(6*2) (a^(6*2)c^(3*2) =
196a^8b^12(a^12c^6) = 196a^20b^12c^6
We can see that
There are four triangle on the surface
and five squares
For finding surface areas , we will find area of each surface and then add them
Calculation of area of triangle:
We are given
base=b=8
height=h=10
now, we can use area formula



Calculation of area of square:
base=width=8


There are four triangle and five squares on the surface
so, we can find surface area
SA=4* triangle + 5*square


so, surface area is
.............Answer