<u>EXPLANATION</u><u>:</u>
Given set A = { 1,2,3}
n(A) = 3
Let the n(B) be n
Total number of relations from A to B = 2^(3×n) =2^3n
According to the given problem
Total relations are = 512
⇛2^3n = 512
⇛2^3n = 2⁹
If bases are equal then exponents must be equal
⇛3n = 9
⇛n = 9/3
⇛n = 3
<h3>So, Number of elements in the set B = 3</h3>
Answer:
<h3>a = 15</h3>
Step-by-step explanation:
5a - 5 - 15 = 3a + 6 + 4 <em>combine like terms</em>
5a + (-5 - 15) = 3a + (6 + 4)
5a - 20 = 3a + 10 <em>add 20 to both sides</em>
5a = 3a + 30 <em>subtract 3a from both sides</em>
2a = 30 <em>divide both sides by 2</em>
a = 15
Answer:
C
Step-by-step explanation:
Mean is all the numbers divided by the amount of numbers listed and Median is what ever number is in the middle (when in order of value). when there's not a exact middle number u add the two numbers in the middle and divide it by two
Check the picture below, so the hyperbola looks more or less like so, so let's find the length of the conjugate axis, or namely let's find the "b" component.
![\textit{hyperbolas, horizontal traverse axis } \\\\ \cfrac{(x- h)^2}{ a^2}-\cfrac{(y- k)^2}{ b^2}=1 \qquad \begin{cases} center\ ( h, k)\\ vertices\ ( h\pm a, k)\\ c=\textit{distance from}\\ \qquad \textit{center to foci}\\ \qquad \sqrt{ a ^2 + b ^2} \end{cases} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Ctextit%7Bhyperbolas%2C%20horizontal%20traverse%20axis%20%7D%20%5C%5C%5C%5C%20%5Ccfrac%7B%28x-%20h%29%5E2%7D%7B%20a%5E2%7D-%5Ccfrac%7B%28y-%20k%29%5E2%7D%7B%20b%5E2%7D%3D1%20%5Cqquad%20%5Cbegin%7Bcases%7D%20center%5C%20%28%20h%2C%20k%29%5C%5C%20vertices%5C%20%28%20h%5Cpm%20a%2C%20k%29%5C%5C%20c%3D%5Ctextit%7Bdistance%20from%7D%5C%5C%20%5Cqquad%20%5Ctextit%7Bcenter%20to%20foci%7D%5C%5C%20%5Cqquad%20%5Csqrt%7B%20a%20%5E2%20%2B%20b%20%5E2%7D%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
Answer:
b = 55 degrees
Step-by-step explanation:
The angles 30, a, b and 45 must sum up to 180 degrees
Subtracting (30 + 45) from both sides leaves us with a + b = 105 degrees.
But b = a + 5. Substituting a + 5 in the equation above yields
a + a + 5 = 105 degrees, so that
2a = 100 degrees, and a = 50 degrees. Then b = a + 5, or b = 55 degrees.
