How I can resolve this please help me this is my son homework

Mathematics

2 answers:

diamong [38]3 years ago

7 0

The second one would be:
321
541
676
694

Serhud [2]3 years ago

3 0

It’s going from least to greatest. For the first problem on the hundreds side it would be
225
437
572
732
Hope this helps

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If you answer this question correctly I will answer 1 of your questions

amm1812

We can start by solving for 10-5a+(18-b). By plugging in a and b, we get

10 - 10 + (18 - 11)= 7

28 ÷ (a × 2) = 28/4 = 7

20 + b − (4 × a) = 31 - 8 = 23

49 − 43 + (a ÷ a) = 49 - 43 + 1 = 7

30 − 25 + (b − 9) = 5 + 2 = 7

50 ÷ a − (b + 20) = 25 - 31 = -6

So, 28 ÷ (a × 2), 49 − 43 + (a ÷ a), and 30 − 25 + (b − 9) will all have the same answer as 10−5a+(18−b)

5 0

3 years ago

Which of the following describes the graph of y = StartRoot negative 4 x minus 36 EndRoot compared to the parent square root fun

RoseWind [281]

Answer:

stretched by a factor of 2, reflected over the y-axis, and translated 9 units left

Step-by-step explanation:

The given function is $y=\sqrt{-4x-36}$

We can rewrite this function by factoring -4 in the radicand to get:

$y=\sqrt{-4(x+9)}$

We further simplify the square root of 4 to get:

$y=2\sqrt{-(x+9)$

The parent function is $y=\sqrt{x}$

When we compare to the parent function, there is a stretch by a factor of 2, reflection over the y-axis, and translation 9 units left

The last option is correct

3 0

4 years ago

Read 2 more answers

how many numbers between 650 and 780 leave remainders of 4 and 6 when divided by 7 and 11 respectively? pls help lol im desperat

Tanya [424]

Answer:

18 numbers between 650 and 780 leave remainders of 4 when divided by 7.

12 numbers between 650 and 780 leave remainders of 6 when divided by 11.

Step-by-step explanation:

1. Number 655 is the smallest number that leaves the remainder of 4 when divided by 7. Number 774 is the greatest number that leaves the remainder of 4 when divided by 7. So,

$a_1=655\\ \\a_n=774\\ \\d=7\\ \\a_n=a_1+(n-1)d\Rightarrow 774=655+7(n-1)\\ \\7(n-1)=774-655\\ \\7(n-1)=119\\ \\n-1=17\\ \\n=17+1=18$

2. Number 655 is the smallest number that leaves the remainder of 6 when divided by 11. Number 776 is the greatest number that leaves the remainder of 6 when divided by 11. So,

$a_1=655\\ \\a_n=776\\ \\d=11\\ \\a_n=a_1+(n-1)d\Rightarrow 776=655+11(n-1)\\ \\11(n-1)=776-655\\ \\11(n-1)=121\\ \\n-1=11\\ \\n=11+1=12$