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Lesechka [4]
3 years ago
14

The table shows the attendance at the art show for the past week.

Mathematics
2 answers:
Vinvika [58]3 years ago
7 0

Answer:

D. 50

Step-by-step explanation:

7*30 - (54+29+22+28+12+15)

=210 - 160

=50

Butoxors [25]3 years ago
6 0

Answer:

50 or D

Step-by-step explanation:

I did the quiz

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kondor19780726 [428]

Answer:

y = 1x + 7

Step-by-step explanation:

<u>The equation formula for this scenario is y = mx + b</u>

m = slope

b = y-intercept

To find the slope, pick two points. I picked (2,9) and (4,11).

Subtract 11 from 9, you'll get 2.

Subtract 4 from 2, you'll get 2.

2/2 equals 1.     The slope (m) = 1

To find the b, y-intercept, plot the points on a graph and see if the linear line across the y-intercept.  For this case, the y-intercept is 7.

The equation is:  y = 1x + 7

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Which is the rate of change for the interval between –6 and –3 on the x-axis?
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A. -2 is the correct answer for the rate of change
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A study was recently conducted at a major university to estimate the difference in the proportion of business school graduates w
sveta [45]

Answer:

(0.1875-0.274) - 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.1412  

(0.1875-0.274) + 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.0318  

And the 95% confidence interval would be given (-0.1412;-0.0318).  

We are confident at 95% that the difference between the two proportions is between -0.1412 \leq p_A -p_B \leq -0.0318

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

p_A represent the real population proportion for business  

\hat p_A =\frac{75}{400}=0.1875 represent the estimated proportion for Business

n_A=400 is the sample size required for Business

p_B represent the real population proportion for non Business

\hat p_B =\frac{137}{500}=0.274 represent the estimated proportion for non Business

n_B=500 is the sample size required for non Business

z represent the critical value for the margin of error  

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})  

Solution to the problem

The confidence interval for the difference of two proportions would be given by this formula  

(\hat p_A -\hat p_B) \pm z_{\alpha/2} \sqrt{\frac{\hat p_A(1-\hat p_A)}{n_A} +\frac{\hat p_B (1-\hat p_B)}{n_B}}  

For the 95% confidence interval the value of \alpha=1-0.95=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.  

z_{\alpha/2}=1.96  

And replacing into the confidence interval formula we got:  

(0.1875-0.274) - 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.1412  

(0.1875-0.274) + 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.0318  

And the 95% confidence interval would be given (-0.1412;-0.0318).  

We are confident at 95% that the difference between the two proportions is between -0.1412 \leq p_A -p_B \leq -0.0318

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2 divided by 5 = 0.4
2/5 = 0.4
2/5 is equal to 0.4
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