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3 years ago

The table shows the attendance at the art show for the past week.

Mathematics

2 answers:

Vinvika [58]3 years ago

7 0

Answer:

D. 50

Step-by-step explanation:

7*30 - (54+29+22+28+12+15)

=210 - 160

=50

Butoxors [25]3 years ago

6 0

Answer:

50 or D

Step-by-step explanation:

I did the quiz

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Help brainliest if right

kondor19780726 [428]

Answer:

y = 1x + 7

Step-by-step explanation:

<u>The equation formula for this scenario is y = mx + b</u>

m = slope

b = y-intercept

To find the slope, pick two points. I picked (2,9) and (4,11).

Subtract 11 from 9, you'll get 2.

Subtract 4 from 2, you'll get 2.

2/2 equals 1. The slope (m) = 1

To find the b, y-intercept, plot the points on a graph and see if the linear line across the y-intercept. For this case, the y-intercept is 7.

The equation is: y = 1x + 7

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3 years ago

Which is the rate of change for the interval between –6 and –3 on the x-axis?

Naya [18.7K]

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3 years ago

Read 2 more answers

A study was recently conducted at a major university to estimate the difference in the proportion of business school graduates w

sveta [45]

Answer:

$(0.1875-0.274) - 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.1412$

$(0.1875-0.274) + 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.0318$

And the 95% confidence interval would be given (-0.1412;-0.0318).

We are confident at 95% that the difference between the two proportions is between $-0.1412 \leq p_A -p_B \leq -0.0318$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$p_A$ represent the real population proportion for business

$\hat p_A =\frac{75}{400}=0.1875$ represent the estimated proportion for Business

$n_A=400$ is the sample size required for Business

$p_B$ represent the real population proportion for non Business

$\hat p_B =\frac{137}{500}=0.274$ represent the estimated proportion for non Business

$n_B=500$ is the sample size required for non Business

$z$ represent the critical value for the margin of error

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

The confidence interval for the difference of two proportions would be given by this formula

$(\hat p_A -\hat p_B) \pm z_{\alpha/2} \sqrt{\frac{\hat p_A(1-\hat p_A)}{n_A} +\frac{\hat p_B (1-\hat p_B)}{n_B}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.