First, distribute the terms.
1(2x^3) = 2x^3
-1(x^2+11) = -x^2-11
Standard form:
2x^3 - x^2 - 11
Since there is a 3, the degree of polynomial is cubic.
There are so many relationships between the original entity and new relation.
The relation mapped from an entity involved in a 1:1 unary relationship contains a foreign key that correspond to its own primary key. 1 to one foreign key will be unique.
The distance formula between two points is d∧2=(x2-x1)∧2 + (y2-y1)∧2
The distance between Vista and Oceanside is
d1∧2=(-1-(-6))∧2+(6-2)∧2=(-1+6)∧2+4∧2=5∧2+16=25+16=41 => d=√41= 6.4
The distance between Oceanside and Alpena is
d2∧2=(0-(-1))∧2+(-1-6)∧2=1+(-7)∧2=1+49=50 => d2=√50=7.07
The distance between Vista and Alpena is
d3∧2=(0-(-6))∧2+(-1-2)∧2=36+9=45 => d3=√45= 6.7
Answer a) is Oceanside and Alpena
Answer b) is Vista and Oceanside
Good luck!!!
Answer:
Step-by-step explanation:
a) 
Substitute limits to get
= 
Thus converges.
b) 10th partial sum =

=
c) Z [infinity] n+1 1 /x ^4 dx ≤ s − sn ≤ Z [infinity] n 1 /x^ 4 dx, (1)
where s is the sum of P[infinity] n=1 1/n4 and sn is the nth partial sum of P[infinity] n=1 1/n4 .
(question is not clear)
Hey, I would be glad to help if i knew what the figure looked like ~