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stepan [7]
3 years ago
14

Suppose you have been tasked with regulating a single monopoly firm that sells 50-pound bags of concrete. The firm has fixed cos

ts of $10 million per year and a variable cost of $3 per bag no matter how many bags are produced.
Mathematics
1 answer:
Oliga [24]3 years ago
7 0
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Work out (4.2×107)÷(7×104)Give your answer in standard form. Work out (4.2×107)÷(7×104)Give your answer in standard form.
professor190 [17]

Answer:

6 * 10^2

Step-by-step explanation:

Simplify : (4.2×10^7)÷(7×10^4)

(4.2 × 10^7) / (7 × 10^4)

From indices : 10^a ÷ 10^b = 10^(a - b)

(4.2 / 7) * 10^(7-4)

0.6 * 10^3

= 6 * 10^2

Hence, (4.2×10^7)÷(7×10^4) = 6 * 10^2

6 0
3 years ago
Congratulations! You won a free grill in a sweepstakes! You know that you can fit a rectangular grill in your truck that has a w
Basile [38]

Answer: 20 feet perimeter is the largest allowed

Step-by-step explanation:  width=2.5 length=no more than 3x2.5

so find longest possible length allowed...

2.5x3=7.5

calculate largest perimeter allowed...

2(7.5+2.5)=20

8 0
2 years ago
Any help? I'm struggling.
Oksi-84 [34.3K]

Answer:

Step-by-step explanation:

a=-7

r=21/-7=-3

a_{15}=a r^{n-1}=-7(-3)^{15-1}=-7(-3)^{14}=-33480783

4 0
2 years ago
What is the answer to -6<21
adell [148]

Answer:

Step-by-step explanation:

I've already answered this question.

8 0
3 years ago
Suppose a consumer group suspects that the proportion of households that have three cell phones NOT known to be 30%. A cell phon
leva [86]

Answer:

We conclude that the actual percentage of households is equal to 30%.

Step-by-step explanation:

We are given that a consumer group suspects that the proportion of households that have three cell phones NOT known to be 30%.

Their marketing people survey 150 households with the result that 43 of the households have three cell phones.

Let p = <u><em>proportion of households that have three cell phones NOT known.</em></u>

So, Null Hypothesis, H_0 : p = 30%      {means that the actual percentage of households is equal to 30%}

Alternate Hypothesis, H_A : p \neq 30%     {means that the actual percentage of households different from 30%}

The test statistics that would be used here <u>One-sample z-test for proportions;</u>

                                T.S. =  \frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of households having three cell phones = \frac{43}{150} = 0.29

           n = sample of households = 150

So, <u><em>the test statistics</em></u>  =  \frac{0.29-0.30}{\sqrt{\frac{0.30(1-0.30)}{150} } }  

                                     =  -0.27

The value of z test statistic is -0.27.

<u>Also, P-value of the test statistics is given by;</u>

              P-value = P(Z < -0.27) = 1 - P(Z \leq 0.27)

                            = 1 - 0.6064 = <u>0.3936</u>

<u>Now, at 1% significance level the z table gives critical value of -2.58 and 2.58 for two-tailed test.</u>

Since our test statistic lies within the range of critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <em><u>we fail to reject our null hypothesis</u></em>.

Therefore, we conclude that the actual percentage of households is equal to 30%.

4 0
3 years ago
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