Pls help me with this

Mathematics

1 answer:

Nonamiya [84]3 years ago

5 0

22 True For all real Numbers A and B, A - B = -B + A

23 True For all real Numbers P, Q, and R, P - Q - R = P - R - Q

24) True For all real Numbers X, Y, Z and (X + Y ) + Z = Z + (X + Y)

25) False For all real Numbers M and N, M/M * N = N/N ==> Example: 5/5 * 3 ≠ 3/3 * 5

26) Examples:

Counterexamples =====> 5 - 0 = 5; 5/1 = 5

5 - 3 ≠ 3 - 5; (5 - 3 ) - 2 ≠ 5 - (3 - 2 );

6/3 ≠ 3/6; (24/6 )/2 ≠ 24/ (6/ 2 )

Hope that helps!!!! : )

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Solve for the unknown angle measures of the polygon. The measures of 13 of the 14 angles of a 14−gon add up to 2,040°. What must

Jet001 [13]

Answer: The measure of fourteenth angle is 120°.

Step-by-step explanation:

Since we have given that

Total number of angles in 14 gon = 14

Sum of measures of 13 angles = 2040°

As we know that sum of all angles in 14 gon would be

$(14-2)\times 180^\circ\\\\=12\times 180^\circ\\\\=2160^\circ$

So, the measure of fourteenth angle would be

$\sum_{x=1}^{13}+x_{14}=2160^\circ\\\\2040^\circ+x_{14}^\circ=2160^\circ\\\\x_{14}^\circ=2160-2040\\\\x_{14}^\circ=120^\circ$

Hence, the measure of fourteenth angle is 120°.

6 0

3 years ago

A model rocket is launched from the ground with an initial velocity of 160 ft/sec. how long will it take the rocket to reach its

timama [110]

The formula we need is
$h(t)=-16t^2+v_0 t+h_0$ , where v₀ is the starting velocity and h₀ is the initial height. Using the velocity and starting height from our problem we have
$h(t)=-16t^2+160t+0$ . The path of this rocket will be a downward facing parabola, so there will be a maximum. This maximum will be at the vertex of the graph. To find the vertex we start out with $x= \frac{-b}{2a}$ , which in our case is $x= \frac{-160}{2(-16)}= \frac{-160}{-32} = 5$ . It will take 5 seconds for the rocket to reach its maximum height. Plugging this back into our formula gives us
$h(5)=-16(5^2)+160(5)+0
\\=-16(25)+800
\\=-400+800=400$
The rocket's maximum height is 400 feet.
We set our formula equal to zero to find the time it takes to hit the ground, then we factor:
$0=-16t^2+160t+0
\\0=-16t^2+160t
\\0=-16t(t-10)$
Using the zero product property, we know that either -16t =0 or t-10=0. When -16t=0 is at t=0, when the rocket is launched. t-10=0 gives us an answer of t=10, so the rocket reaches the ground again at 10 seconds.

8 0

3 years ago

X over 3/4 =7/8 put answer in fraction form first answer get brainliest

Inessa05 [86]

Answer:

$\frac{21}{32} = x$