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3 years ago

If b=6, find the value of 7b

Mathematics

2 answers:

Serggg [28]3 years ago

5 0

7b is just 7 x b and if b is 6 its just 7 x 6
which the answer is 42

Bezzdna [24]3 years ago

3 0

7 times 6 = 42, since b=6 we substitute in the value, so it's basically 7 times 6

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What’s 8 squared into a decimal

ycow [4]

Answer:

2.828 i think

Step-by-step explanation:

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2 years ago

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what is an equation of the line that s perpendicullar to y-3=-4(x+2) and passes through the point (-5,7)

Sidana [21]

Answer:

4y=x+33

y=x/4+33/4 (slope-intercept form)

Step-by-step explanation:

y-3 = -4(x+2)

y-3 -4x-8

y= -4x-8+3

y= -4x-5

m1 = -4

For perpendicularity

m2= -1/-4 = 1/4

The equation is

y-y1 = m2(x-x1)

y-7 = 1/4(x-(-5))

y-7 = x/4+5/4

Multiply through by 4

4y-28=x+5

4y=x+5+28

4y=x+33

Divide through by 4

y=x/4+33/4 (slope-intercept form)

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3 years ago

What is the unit rate of $46 for 5 toys

Nookie1986 [14]

I think it would be $9.20 because 46 divided by 5 = 9.2

8 0

2 years ago

Which statement best reflects the solution(s) of the equation?

Inessa [10]

x=2 is only solution while x=1 is extraneous solution

Option C is correct.

Step-by-step explanation:

We need to solve the equation $\frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}$ and find values of x.

Solving:

Find the LCM of denominators x-1,x and x-1. The LCM is x(x-1)

Multiply the entire equation with x(x-1)

$\frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}\\\frac{1}{x-1}*x(x-1)+\frac{2}{x}*x(x-1)=\frac{x}{x-1}*x(x-1)\\Cancelling\,\,out\,\,the\,\,same\,\,terms:\\x+2(x-1)=x^2\\x+2x-2=x^2\\3x-2=x^2\\x^2-3x+2=0$

Now, factoring the term:

$x^2-2x-x+2=0\\x(x-2)-1(x-2)=0\\(x-1)(x-2)=0\\x-1=0\,\,and\,\, x-2=0\\x=1\,\,and\,\, x=2$

The values of x are x=1 and x=2

Checking for extraneous roots:

Extraneous roots: The root that is the solution of the equation but when we put it in the equation the answer turns out not to be right.

If we put x=1 in the equation, $\frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}$ the denominator becomes zero i.e

$\frac{1}{1-1}+\frac{2}{1}=\frac{1}{1-1}\\\frac{1}{0}+2=\frac{1}{0}$

which is not correct as in fraction anything divided by zero is undefined. So, x=1 is an extraneous solution.

If we put x=2 in the equation,

$\frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}$

$\frac{1}{2-1}+\frac{2}{2}=\frac{2}{2-1}\\\frac{1}{1}+1=\frac{2}{1}\\1+1=2\\2=2$

So, x=2 is only solution while x=1 is extraneous solution

Option C is correct.

Keywords: Solving Equations and checking extraneous solution

Learn more about Solving Equations and checking extraneous solution at:

#learnwithBrainly

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3 years ago

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LenKa [72]

The answer to this question is 3.75

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2 years ago