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3 years ago

Data represented by quantities is called data.

1 answer:

3 0

Four types of data (nominal, ordinal, interval, and ratio) that represent values or observations that can be sorted into a category

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PLEASE HELP ME ! IMAGE IS BELOW IF YOU GET IT RIGHT I'LL MARK BRAINLIEST

jarptica [38.1K]

Answer:

x = 17

y = 8

QPR = 35º

QRP = 60º

Step-by-step explanation:

2x + 1 = x + 18

Subtract x from both sides

x + 1 = 18

Subtract 1 from both sides

x = 17

QPR = 2x + 1

QPR = 2(17) + 1

QPR = 35º

-------------------------------

8y - 4 = 4y + 28

Subtract 4y from both sides

4y - 4 = 28

Add 4 to both sides

4y = 32

Divide both sides by 4

y = 8

QPR = 8y - 4

QRP = 8(8) - 4

QRP = 60º

7 0

3 years ago

Solve using Fourier series.

Olin [163]

With $2L=\pi$ , the Fourier series expansion of $f(x)$ is

$\displaystyle f(x)\sim\frac{a_0}2+\sum_{n\ge1}a_n\cos\dfrac{n\pi x}L+\sum_{n\ge1}b_n\sin\dfrac{n\pi x}L$
$\displaystyle f(x)\sim\frac{a_0}2+\sum_{n\ge1}a_n\cos2nx+\sum_{n\ge1}b_n\sin2nx$

where the coefficients are obtained by computing

$\displaystyle a_0=\frac1L\int_0^{2L}f(x)\,\mathrm dx$
$\displaystyle a_0=\frac2\pi\int_0^\pi f(x)\,\mathrm dx$

$\displaystyle a_n=\frac1L\int_0^{2L}f(x)\cos\dfrac{n\pi x}L\,\mathrm dx$
$\displaystyle a_n=\frac2\pi\int_0^\pi f(x)\cos2nx\,\mathrm dx$

$\displaystyle b_n=\frac1L\int_0^{2L}f(x)\sin\dfrac{n\pi x}L\,\mathrm dx$
$\displaystyle b_n=\frac2\pi\int_0^\pi f(x)\sin2nx\,\mathrm dx$

You should end up with

$a_0=0$
$a_n=0$
(both due to the fact that $f(x)$ is odd)
$b_n=\dfrac1{3n}\left(2-\cos\dfrac{2n\pi}3-\cos\dfrac{4n\pi}3\right)$

Now the problem is that this expansion does not match the given one. As a matter of fact, since $f(x)$ is odd, there is no cosine series. So I'm starting to think this question is missing some initial details.

One possibility is that you're actually supposed to use the even extension of $f(x)$ , which is to say we're actually considering the function

$\varphi(x)=\begin{cases}\frac\pi3&\text{for }|x|\le\frac\pi3\\0&\text{for }\frac\pi3$

and enforcing a period of $2L=2\pi$ . Now, you should find that

$\varphi(x)\sim\dfrac2{\sqrt3}\left(\cos x-\dfrac{\cos5x}5+\dfrac{\cos7x}7-\dfrac{\cos11x}{11}+\cdots\right)$

The value of the sum can then be verified by choosing $x=0$ , which gives

$\varphi(0)=\dfrac\pi3=\dfrac2{\sqrt3}\left(1-\dfrac15+\dfrac17-\dfrac1{11}+\cdots\right)$
$\implies\dfrac\pi{2\sqrt3}=1-\dfrac15+\dfrac17-\dfrac1{11}+\cdots$

as required.

5 0

3 years ago

What is the prime factorization of 200? 2 2 × 5 3 2 3 × 5 2 2 4 × 5 2 × 5 4

Misha Larkins [42]

Answer:

2^3 * 5^2

Step-by-step explanation:

We need to break 200 down into prime numbers

200 = 20*10 These are not prime

= 4*5 * 2*5 The 4 is not prime

= 2*2*5 * 2*5 This is prime

Rearranging

= 2*2*2*5*5

= 2^3 * 5^2

8 0

3 years ago

Find (h-f)(x)???????

vichka [17]

Multiply both variables individually by the multiplied variable (x)... and you find yourself with -fx + hx.... Remember to bring that negative integer along too or the answere that I have without a negative integer won't count... I hope this clarified your understanding and question. As always good spiruts

8 0

3 years ago

According to Internet security experts, approximately 90% of all e-mail messages are spam (unsolicited commercial e-mail), while

KonstantinChe [14]

Answer:

0.0656

Step-by-step explanation:

For each message, we have these following probabilities:

90% probability it is spam.

10% probability it is legitimate.

Compute the probability that the first legitimate e-mail she finds is the fifth message she checks:

The first four all spam, each with a 90% probability.

The fifth legitimate, with a 10% probability.

$P = (0.9)^{4} \times 0.1 = 0.0656$

3 0

3 years ago