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Darya [45]
3 years ago
5

Suppose the function F(c) represents the earnings of a volleyball team from selling c cupcakes. They are selling each cupcake fo

r $2 each.
Which variable represents the domain? Interpret what it is in context.


Do positive or negative (or both) values for the input make sense in the context? Describe an appropriate domain of this function. Specify the upper limit and the lower limit.


Is it possible for the team to earn $50.50?


Please! I need help!
Mathematics
2 answers:
r-ruslan [8.4K]3 years ago
8 0

Answer:

c (no. of cupcakes)

No, only positive values

Appropriate domain: while numbers

Lower limit: 0, upper limit: positive infinity

Not possible

Step-by-step explanation:

Domain is the set of inputs/independent variable

Which in this case is no. of cupcakes sold

The domain can take values which are whole numbers,

0, 1, 2,..... infinity

F(c) = 50.50

2c = 50.50

c = 25.25 (not possible)

navik [9.2K]3 years ago
5 0

Answer:

The variable c represents the domain as it is the independent variable.

The domain of the function F(c) is given by c ≥ 0.

So, only positive values for the input make sense.

The upper limit of the domain is +∞ and lower limit is 0.

It is not possible for the team to earn $50.50 as it will be only multiple of 2.

Step-by-step explanation:

If F(c) represents the earning of a volleyball team from selling c cupcakes and each cupcake costs $2 each, then the equation that models the situation is  

F(c) = 2c ..... (1)

The variable c represents the domain as it is the independent variable. (Answer)

The domain of the function F(c) is given by c ≥ 0. (Answer)

So, only positive values for the input make sense. (Answer)

The upper limit of the domain is +∞ and the lower limit is 0. (Answer)

It is not possible for the team to earn $50.50 as it will be only multiple of 2. (Answer)

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\int_{0}^{\frac{3 \pi}{4}}3 \cos{\left(x \right)}\ dx\approx 3.099558

Step-by-step explanation:

We want to find the Riemann sum for \int_{0}^{\frac{3 \pi}{4}}3 \cos{\left(x \right)}\ dx with n = 6, using left endpoints.

The Left Riemann Sum uses the left endpoints of a sub-interval:

\int_{a}^{b}f(x)dx\approx\Delta{x}\left(f(x_0)+f(x_1)+2f(x_2)+...+f(x_{n-2})+f(x_{n-1})\right)

where \Delta{x}=\frac{b-a}{n}.

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We have that a=0, b=\frac{3\pi }{4}, n=6

Therefore, \Delta{x}=\frac{\frac{3 \pi}{4}-0}{6}=\frac{\pi}{8}

Step 2: Divide the interval \left[0,\frac{3 \pi}{4}\right] into n = 6 sub-intervals of length \Delta{x}=\frac{\pi}{8}

a=\left[0, \frac{\pi}{8}\right], \left[\frac{\pi}{8}, \frac{\pi}{4}\right], \left[\frac{\pi}{4}, \frac{3 \pi}{8}\right], \left[\frac{3 \pi}{8}, \frac{\pi}{2}\right], \left[\frac{\pi}{2}, \frac{5 \pi}{8}\right], \left[\frac{5 \pi}{8}, \frac{3 \pi}{4}\right]=b

Step 3: Evaluate the function at the left endpoints

f\left(x_{0}\right)=f(a)=f\left(0\right)=3=3

f\left(x_{1}\right)=f\left(\frac{\pi}{8}\right)=3 \sqrt{\frac{\sqrt{2}}{4} + \frac{1}{2}}=2.77163859753386

f\left(x_{2}\right)=f\left(\frac{\pi}{4}\right)=\frac{3 \sqrt{2}}{2}=2.12132034355964

f\left(x_{3}\right)=f\left(\frac{3 \pi}{8}\right)=3 \sqrt{\frac{1}{2} - \frac{\sqrt{2}}{4}}=1.14805029709527

f\left(x_{4}\right)=f\left(\frac{\pi}{2}\right)=0=0

f\left(x_{5}\right)=f\left(\frac{5 \pi}{8}\right)=- 3 \sqrt{\frac{1}{2} - \frac{\sqrt{2}}{4}}=-1.14805029709527

Step 4: Apply the Left Riemann Sum formula

\frac{\pi}{8}(3+2.77163859753386+2.12132034355964+1.14805029709527+0-1.14805029709527)=3.09955772805315

\int_{0}^{\frac{3 \pi}{4}}3 \cos{\left(x \right)}\ dx\approx 3.099558

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