So it tells us that g(3) = -5 and g'(x) = x^2 + 7.
So g(3) = -5 is the point (3, -5)
Using linear approximation
g(2.99) is the point (2.99, g(3) + g'(3)*(2.99-3))
now we just need to simplify that
(2.99, -5 + (16)*(-.01)) which is (2.99, -5 + -.16) which is (2.99, -5.16)
So g(2.99) = -5.16
Doing the same thing for the other g(3.01)
(3.01, g(3) + g'(3)*(3.01-3))
(3.01, -5 + 16*.01) which is (3.01, -4.84)
So g(3.01) = -4.84
So we have our linear approximation for the two.
If you wanted to, you could check your answer by finding g(x). Since you know g'(x), take the antiderivative and we will get
g(x) = 1/3x^3 + 7x + C
Since we know g(3) = -5, we can use that to solve for C
1/3(3)^3 + 7(3) + C = -5 and we find that C = -35
so that means g(x) = (x^3)/3 + 7x - 35
So just to check our linear approximations use that to find g(2.99) and g(3.01)
g(2.99) = -5.1597
g(3.01) = -4.8397
So as you can see, using the linear approximation we got our answers as
g(2.99) = -5.16
g(3.01) = -4.84
which are both really close to the actual answer. Not a bad method if you ever need to use it.
Answer:

Step-by-step explanation:
Given: Marisa bought four bottles
Price of each bottle is $0.95.
Solving with the factors as given to find the total cost paid by Marisa.
Total cost= 
∴ Total cost paid by Marisa is $3.8.
As given to write an equation with the same product as the total cost but different factors.
∴ Lets assume the number of bottles bought by Marisa be "5" and cost of each bottle be "x"
We already find the total cost she paid is $3.8.
Now, writing an equation with different factors, as total cost remain same.

Dividing both side by 5
we get x= $ 0.76
∴ The required equation is 
Answer:
Therefore 200.96 ft.of fencing are needed to go around the pool path.
Step-by-step explanation:
Given, a circular swimming pool has a radius of 28ft. There is a path all the way around the pool. The width of the path 4 ft.
The radius of the outside edge the pool path is
= Radius of the pool + The width of the path
= (28+4) ft
= 32 ft.
To find the length of fencing, we need to find the circumference of outside the pool path.
Here r= 32 ft
The circumference of outside edge of the pool path
=

=200.96 ft.
Therefore 200.96 ft.of fencing are needed to go around the pool path.
Answer:
Equation shown
Step-by-step explanation:
Eq(1): x-3y=-12
X=-12+3y
=-4+y
Eq(2): x-3y=-6
X=-6+3y
=-2+y
= 5/3 x (-7/2)
= -35/6
= -5 5/6
answer A.
-5 5/6