Answer:
Infinite solutions
Step-by-step explanation:
1) First, you can solve this easily by elimination. Multiply the first equation by -2 in order to cancel out terms when adding to the second equation.
2) Then, add the new set of equations together. However, everything cancels out, bringing us to 0 = 0. This means that the lines the equations make must be the same. Thus, all real numbers must make this equation true, meaning that there are infinite solutions.
Answer:
-4,3.5
Step-by-step explanation:
1st one
x-2x-20 = 12
-x = 32
x=-4
2nd one
-15=15q-50 - 5q
35= 10q
q = 3.5
The best method for solving the system of linear equation is by the use of algebraic methods.
The system of linear equations can be solved by using the method of simultaneous equations. Here we are given two equations and two unknown variables. We can solve the same by eliminating one of the variables and then either adding or subtracting, find the value of the other variable. Once we know the value of one variable, then we can substitute its value in any one given equation and find the second variable. This method is said to be accurate and does not involve any error.
Hence answer is : USE ALGEBRAIC METHODS
Answer:
a) The function is constantly increasing and is never decreasing
b) There is no local maximum or local minimum.
Step-by-step explanation:
To find the intervals of increasing and decreasing, we can start by finding the answers to part b, which is to find the local maximums and minimums. We do this by taking the derivatives of the equation.
f(x) = ln(x^4 + 27)
f'(x) = 1/(x^2 + 27)
Now we take the derivative and solve for zero to find the local max and mins.
f'(x) = 1/(x^2 + 27)
0 = 1/(x^2 + 27)
Since this function can never be equal to one, we know that there are no local maximums or minimums. This also lets us know that this function will constantly be increasing.
