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2 years ago

The model represents an equation. What is the solution for the equation?

Mathematics

1 answer:

ryzh [129]2 years ago

7 0

Answer: A x = 3

Step-by-step explanation:

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Take away 32 from the product of 6 and a number

Sphinxa [80]

6x-32 is the expression that you are looking for

4 0

2 years ago

42minutes:5hours in ratio form

TiliK225 [7]

Answer:

31:150

Step-by-step explanation:

First of all we convert the hours into minutes:

5×60=300

which gets us 42:300, which we can simplify to:

31:150

and is 31 is prime and 150 can't be divided into it without a remainder, it is in it's simplest form and it is the answer.

8 0

2 years ago

Read 2 more answers

What is the solution set of the equation using the quadratic formula?

oee [108]

(1)

we are given

$x^2+6x+10=0$

we can use quadratic formula

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}$

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

now, we can compare and find a , b and c

we get

$a=1,b=6,c=10$

now, we can plug these values into quadratic formula

$x=\frac{-6\pm \sqrt{6^2-4(1)(10)}}{2(1)}$

$x=\frac{-6+\sqrt{6^2-4\cdot \:1\cdot \:10}}{2\cdot \:1}$

we can simplify it

$x=-3+i$

$x=\frac{-6-\sqrt{6^2-4\cdot \:1\cdot \:10}}{2\cdot \:1}$

$x=-3-i$

so, we will get solution

{−3+i, −3−i}.........Answer

(2)

we are given equation as

$x^2-8x+14=0$

Since, Jamal solve this equation by completing square

so, firstly we will move constant term on right side

so, subtract both sides by 14

$x^2-8x+14-14=0-14$

$x^2-8x=-14$

we can write

$-8x=-2\times 4\times x$

so, we will add both sides by 4^2

$x^2-8x+4^2=-14+4^2$

we get

$x^2-8x+16=-14+16$ ..............Answer

4 0

2 years ago

2. A sprinter is running at the end of a race and begins to tire. Her velocity is 8.55 m/s and is decelerating at -0.15m/s for t

GrogVix [38]

Step-by-step explanation:

using the formula :

2.d.s = V²-Vo²

2(-0.15) (60) = V² - (8.55)²

-18 = V² - 73.1

V² = 73.1 - 18

V² = 55.1

=> V = √55.1 = 7.4

so, the velocity when she ends the race =

7.4 m/s

3 0

2 years ago

PLEASE HELP!

Ilia_Sergeevich [38]

You have the function $y= \dfrac{60x}{1+0.625x}$ .
Rewrite it in the following way:

$y= \dfrac{60x}{1+0.625x}=\dfrac{60x}{1+ \frac{5}{8} x}=\dfrac{480x}{8+5x}=\dfrac{96\cdot 5x}{8+5x}=$
$=\dfrac{96(5x+8-8)}{8+5x}=\dfrac{96(5x+8)}{8+5x}-\dfrac{96\cdot8}{8+5x}=96-\dfrac{768}{8+5x}$ .
This function entry allows you to determine that y=96 is the horizontal asymptote and x=-8/5 is the vertical asymptote.

From the added graph of the function you can conclude that the maximum number of moose that the forest can sustain at one time is 96.
Answer: Correct choice is A.

8 0

3 years ago