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stealth61 [152]
3 years ago
8

The model represents an equation. What is the solution for the equation?

Mathematics
1 answer:
ryzh [129]3 years ago
7 0

Answer: A x = 3

Step-by-step explanation:

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Find x: 2(4x − 3) − 8 = 4 + 2x
MariettaO [177]
X = 3

2(4x - 3) - 8 = 4 + 2x

1. Distribute

8x - 6 - 8 = 4 + 2x

2. Collect like terms

8x - 14 = 4 + 2x

3. Collect like terms again (add 14 and subtract 2x)

6x = 18

4. Divide by 6

x = 3
4 0
3 years ago
Read 2 more answers
30 points!<br> You start at (-2, 2). You move left 3 units and right 10 units. Where do you end?
Cerrena [4.2K]

Answer:

The answer is (5, 2)

Step-by-step explanation:

I. If move left = -x

    move right = +x

  So -2 - 3 =  -5 => move left

        -5 + 10 = 5 => move right

I suggest that move left and right is x cordinate

The answer is (5,2)

Is that correct?

7 0
3 years ago
A circular swimming pool has a radius of 15 ft. There is a path all the way around that pool that is three feet wide. What is th
daser333 [38]

Answer:

The radius of the circle with the circumfrence we need to find is 15+3=18.

18*2pi=113.04

4 0
3 years ago
How you can use Triangle congruence to solve real-world problems? give 3 examples.
Stells [14]

Answer:

1.Many pairs of triangles designed into a building, for example as roof ends, would be congruent, so the roof beam and the top edges of the walls are horizontal.

2.The congruent triangle is used in most of the building that are design to stay in bad conditions and Strong winds for Example the Sydney Bridge.

3.in real life two triangles are rarely exactly congruent. However they are crucial in the construction of large man-made structures. This is because a triangle is the most stable shape and the congruence is needed to create even surfaces.

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3 years ago
14. Find the slope of a line parallel to 3y - 6x = 9. (Lesson 3-4)
DanielleElmas [232]

\bf 3y-6x=9\implies 3y=6x+9\implies y=\cfrac{6x+9}{3}\implies y = \cfrac{6x}{3}+\cfrac{9}{3} \\\\\\ y = \stackrel{\stackrel{m}{\downarrow }}{2}x+3\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}

a parallel line to that one above, will have the same exact slope, since parallel lines have the same slope.

4 0
3 years ago
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