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stealth61 [152]
3 years ago
8

The model represents an equation. What is the solution for the equation?

Mathematics
1 answer:
ryzh [129]3 years ago
7 0

Answer: A x = 3

Step-by-step explanation:

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How can you solve y=-2x+20 by substitution?
levacccp [35]

Answer:

subtract from both sides and then multiplying both sides

Step-by-step explanation:

how can you solve y = -2x + 25 by subtraction

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What is one-half of the product of the following?
agasfer [191]

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-2/3 is the right answer

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What is the inequaliity of 3<-5n+2n and how do you put it on a number line
timama [110]
The inequality would be the negative factor, because -5n+2n is 3n. You would write it on a number line like this..... 
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A teacher wrote the equation 3y + 12 = 6x on the board. For what value of b would the additional equation 2y = 4x + b form a sys
guajiro [1.7K]
3y + 12 = 6x
3y = 6x - 12
y = 2x - 4

2y = 4x + (-8)
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3 0
3 years ago
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What is the equation of a circle with center (-3, -1) that contains the point (1, 2)?
Leno4ka [110]
So, we know the center is at -3,-1, ok

hmmm what's the radius anyway?   well, we know that there's a point at 1,2 that is on the circle's path...hmmmm what's the distance from the center to that point?  well, is the radius, let's check then.

\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
&({{ -3}}\quad ,&{{ -1}})\quad 
%  (c,d)
&({{ 1}}\quad ,&{{ 2}})
\end{array}\qquad 
%  distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
r=\sqrt{[1-(-3)]^2+[2-(-1)]^2}\implies r=\sqrt{(1+3)^2+(2+1)^2}
\\\\\\
r=\sqrt{16+9}\implies r=\sqrt{25}\implies r=5

so, what's the equation of a circle with center at -3, -1 and a radius of 5?

\bf \textit{equation of a circle}\\\\ 
(x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2
\qquad 
\begin{array}{lllll}
center\ (&{{ h}},&{{\quad  k}})\qquad 
radius=&{{ r}}\\
&-3&-1&5
\end{array} 
\\\\\\\
[x-(-3)]^2+[y-(-1)]^2=5^2\implies (x+3)^2+(y+1)^2=25
7 0
3 years ago
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