The model represents an equation. What is the solution for the equation?

In this problem, the mean blood pressure is calculated for all employees, which means that it is valid for the population, hence it is a parameter.

More can be learned about parameters and statistics at brainly.com/question/13794992

#SPJ1

8 0

2 years ago

The distance from the ground of a person riding on a Ferris wheel can be modeled by the equation d equals 20 times the sine of t

kodGreya [7K]

We have the function d, representing the distance from the ground of a person riding on a Ferris wheel:

$d(t)=20\sin (\frac{\pi}{30}t)+10$

If we consider the position of the person at t = 0, which is:

$d(0)=20\sin (\frac{\pi}{30}\cdot0)+10=20\cdot0+10=10$

This position, for t = 0, will be the same position as when the argument of the sine function is equal to 2π, which is equivalent to one cycle of the wheel. Then, we can find the value of t:

$\begin{gathered} \sin (\frac{\pi}{30}t)=\sin (2\pi) \\ \frac{\pi}{30}\cdot t=2\pi \\ t=2\pi\cdot\frac{30}{\pi} \\ t=60 \end{gathered}$

Then, the wheel will repeat its position after t = 60 seconds.

Answer: 60 seconds.

7 0

1 year ago

SOS PLZ IDK THIS VERY WELL NEED HELP

zaharov [31]

Answer:

1. a. 25(1) + 10(2) + 3(3) + 10(4) = 94/140 = .671

2. b. Mark’s average < Jay’s average

Step-by-step explanation:

1. What is Mark’s slugging average?

The slugging average gives more weight to the multi-base hits (compared to single-base hits) in opposition with the batting average.

So, a single hit is worth 1 point, a double is worth 2 points, a triple 3 points and a homerun is worth 4 points. It's a weighted average calculation.

Mark had 25 singles, 10 doubles, 3 triples and 10 homeruns during 140 presences 140 at bat.

25(1) + 10(2) + 3(3) + 10(4) = 94/140 = .671

2. How does Mark's average compares to Jay's?

Let's first calculate Jay's slugging average then we'll be able to decide.

Jay had 10 singles, 6 doubles, 5 triples and 14 homeruns in 90 presences.

10 (1) + 6 (2) + 5 (3) + 14 (4) = 10+12+15+56 = 93 / 90 = 1.033

We can definitely say that Mark's slugging average (0.671) calculated above is lower than Jay's average (1.033). So,

b. Mark’s average < Jay’s average

8 0

3 years ago