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motikmotik
3 years ago
10

Is the growth of a tree a function of the monthly rainfall?

Mathematics
1 answer:
AfilCa [17]3 years ago
5 0

Answer:


Step-by-step explanation:

For something to be a function of something else, it means that the second thing directly impacts the first thing in some way. Also, you would expect that with the same input, you consistently receive the same output.

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PLEASE HELP ASAP, Major points Geometry
gavmur [86]
Central angle is 130
Semi circle is BED and BCD
Major arc is CEB
Measure BAC is 130
BEC is 230
3 0
3 years ago
​Find all roots: x^3 + 7x^2 + 12x = 0 <br> Show all work and check your answer.
Aliun [14]

The three roots of x^3 + 7x^2 + 12x = 0 is 0,-3 and -4

<u>Solution:</u>

We have been given a cubic polynomial.

x^{3}+7 x^{2}+12 x=0

We need to find the three roots of the given polynomial.

Since it is a cubic polynomial, we can start by taking ‘x’ common from the equation.

This gives us:

x^{3}+7 x^{2}+12 x=0

x\left(x^{2}+7 x+12\right)=0   ----- eqn 1

So, from the above eq1 we can find the first root of the polynomial, which will be:

x = 0

Now, we need to find the remaining two roots which are taken from the remaining part of the equation which is:

x^{2}+7 x+12=0

we have to use the quadratic equation to solve this polynomial. The quadratic formula is:

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Now, a = 1, b = 7 and c = 12

By substituting the values of a,b and c in the quadratic equation we get;

\begin{array}{l}{x=\frac{-7 \pm \sqrt{7^{2}-4 \times 1 \times 12}}{2 \times 1}} \\\\{x=\frac{-7 \pm \sqrt{1}}{2}}\end{array}

<em><u>Therefore, the two roots are:</u></em>

\begin{array}{l}{x=\frac{-7+\sqrt{1}}{2}=\frac{-7+1}{2}=\frac{-6}{2}} \\\\ {x=-3}\end{array}

And,

\begin{array}{c}{x=\frac{-7-\sqrt{1}}{2}} \\\\ {x=-4}\end{array}

Hence, the three roots of the given cubic polynomial is 0, -3 and -4

4 0
3 years ago
The vertex of this parabola is at (2, -4). When the y-value is -1, the x-value is 3. What is the coefficient of the squared term
rjkz [21]

Answer:

3

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Here (h, k) = (2, - 4) , thus

y = a(x - 2)² - 4

To find a substitute (3, - 1 ) into the equation

- 1 = a(3 - 2)² - 4 ( add 4 to both sides )

3 = a

Thus

y = 3(x - 2)2 - 4 ← equation in vertex form

   = 3(x² - 4x + 4) + 4

    = 3x² - 12x + 12 + 4

     = 3x² - 12x + 16 ← equation in standard form

with coefficient of x² term = 3

5 0
4 years ago
Can somebody help me out ??
julia-pushkina [17]
Answer: y = -3/2x -5

explanation:
y = mx + b
7 = -3/2(-8)+b
7= 12 +b
subtract 12 on both sides
-5 = b

y = -3/2x - 5
3 0
3 years ago
Write 11/25 and 9/20 so that they can have a common denominator.
sergejj [24]
Multiple 11/25 with 4 and 9/20 with 5 so it will be
44/100 and 45/100
7 0
3 years ago
Read 2 more answers
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