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bija089 [108]
3 years ago
14

Solve: 8y - 3 > 10y + 21

Mathematics
1 answer:
Brrunno [24]3 years ago
7 0
Answer : y < -12
hope this helps !
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Galina-37 [17]

Step-by-step explanation:

oh, come on. you can just use common sense.

a local minimum is a point where the curve goes down to, and then turns around and starts to go up again. that point in the middle, where it turns around and does not go down any further, is the minimum.

for the maximum the same thing applies, just in the other direction (the curve goes up and turns around to go back down again).

a)

the local minimum values (y) are

-2, -1

b)

the values of x where it had these minimum values are

-1, +3

4 0
2 years ago
What is the degree of 12x4 - 8x + 4x2 - 3?<br><br> A. 8<br> B. 4<br> C. 3<br> D. 12
Soloha48 [4]
In this problem, we are asked to determine the degree of the given expression 12X4 - 8X + 4X2 -3. To answer this, first, we need to arrange the mathematical expression in descending order with respect to its power such as the new arrangement will become 12x4 + 4x2 -8x -3. The degree is clearly visible and it is 4. Therefore, the answer to this problem is the letter "B" which is 4.
4 0
3 years ago
Read 2 more answers
Given that ABDC : EFGH, what is m G?<br> 27°<br> 90°<br> 117°<br> 120°
oksian1 [2.3K]
I think it would be 117

Because H is 63
So 90+90+63=243
360-243=117
I used 360 because angles in quadrilaterals add up to 360 degrees
4 0
3 years ago
Write each number in expanded form and using number names.
stellarik [79]
1. <span><span>20,000 </span><span>+7,000 </span><span>+500 </span><span>+40 </span><span>+9 -----WORD FORM :</span></span>twenty-seven thousand,
five hundred forty-nine

2. <span>Expanded Numbers Form:
</span>
<span><span> 700,000 </span><span>+90,000 </span><span>+2,000 </span><span>+0 </span><span>+60 </span><span>+5 </span></span>
WORD FORM : seven hundred ninety-two thousand,
sixty-five
                                                                               
3 0
4 years ago
Which of the following have the property that a(x)=a−1(x)? I. y=x II. y=1/x III.y=x^2 IV. y=x^3 A. I and II, only B. IV, only C.
valentina_108 [34]

Answer:

<em>Correct answer:</em>

<em>A. I and II</em>

<em></em>

Step-by-step explanation:

First of all, let us have a look at the steps of finding inverse of a function.

1. Replace y with x and x with y.

2. Solve for y.

3. Replace y with f^{-1}(x)

Given that:

I.\ y=x \\II.\ y=\dfrac{1}x \\III.\ y=x^2 \\IV.\ y=x^3

Now, let us find inverse of each option one by one.

I. y = x, a(x) = x

Replacing y with and x with y:

x = y

x = a^{-1}(x) = a(x)  Hence, I is true.

II. y =\dfrac{1}{x}

Replacing y with and x with y:

x =\dfrac{1}{y}

x=\dfrac{1}{a^{-1}(x)}

\Rightarrow a^{-1}(x) = \dfrac{1}{x}

a^{-1}(x) = a(x)  Hence, II is true.

III. y =x^{2}

Replacing y with and x with y:

x =y^{2}\\\Rightarrow y = \sqrt x\\\Rightarrow a^{-1}(x) = \sqrt{x} \ne a(x)

 Hence, III is not true.

IV. y =x^{3}

Replacing y with and x with y:

x =y^{3}\\\Rightarrow y = \sqrt[3] x\\\Rightarrow a^{-1}(x) = \sqrt[3]{x} \ne a(x)

Hence, IV is not true.

<em>Correct answer:</em>

<em>A. I and II</em>

<em></em>

4 0
3 years ago
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