Question

A woman who is colorblind marries a man with normal vision. what are the chances that their daughters will be carriers for colorblindness?

Answer 1

$\frac{1}{4}$
because there mother is colorblind c is carrier gene and b is colorblindness gene
$x^{c} {x}^{b}$
and their dad isn't so
${xy}$
chances:
${x}^{c} {x}$
normal vision daughter and a carrier
${xx}^{b}$
colorblind daughter
${x}^{c}y$
normal vision son and a carrier
${x}^{b} y$
colorblind son