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MAVERICK [17]
3 years ago
13

Jack types 162 words in 3 minutes. Jack types at a constant rate. How many words does Jack type per minute?

Mathematics
1 answer:
Arte-miy333 [17]3 years ago
3 0

Answer:

54

Step-by-step explanation:

162/3 = 54

You might be interested in
The product of two consecutive whole numbers is less than the sum of the square of the smaller number and 13
Norma-Jean [14]

Answer: a<13

Step-by-step explanation:

a*(a+1)<a^2+13

a^2+a<a^2+13

subtract a^2 from both sides:

a<13

8 0
4 years ago
2^2 times 2^3<br> a.2^4<br> b.2^5<br> c.2^6<br> d.4^6
maxonik [38]

Answer:

The quadratic equations and their solutions are;

9 ± √33 /4 = 2x² - 9x + 6.

4 ± √6 /2 = 2x² - 8x + 5.

9 ± √89 /4 = 2x² - 9x - 1.

4 ± √22 /2 = 2x² - 8x - 3.

Explanation:

Any quadratic equation of the form, ax² + bx + c = 0 can be solved using the formula x = -b ± √b² - 4ac / 2a. Here a, b, and c are the coefficients of the x², x, and the numeric term respectively.

We have to solve all of the five equations to be able to match the equations with their solutions.

2x² - 8x + 5, here a = 2, b = -8, c = 5.                                                  x = -b ± √b² - 4ac / 2a = -(-8) ± √(-8)² - 4(2)(5) / 2(2) = 8 ± √64 - 40/4.     24 can also be written as 4 × 6 and √4 = 2. So                                                                                     x = 8 ± 2√6 / 2×2= 4±√6/2.

2x² - 10x + 3, here a = 2, b = -10, c = 3.                                                   x =-b ± √b² - 4ac / 2a =-(-10) ± √(-10)² - 4(2)(3) / 2(4) = 10 ± √100 + 24/4. 124 can also be written as 4 × 31 and √4 = 2. So                                                                              x = 10 ± 2√31 / 2×2 = 5 ± √31 /2.

2x² - 8x - 3, here a = 2, b = -8, c = -3.                                                    x = -b ± √b² - 4ac / 2a = -(-8) ± √(-8)² - 4(2)(-3) / 2(2) = 8 ± √64 + 24/4.     88 can also be written as 4 × 22 and √4 = 2. So                                                                             x = 8 ± 2√22 / 2×2 = 4± √22/2.

2x² - 9x - 1, here a = 2, b = -9, c = -1.                                                     x = -b ± √b² - 4ac / 2a = -(-9) ± √(-9)² - 4(2)(-1) / 2(2) = 9 ± √81 + 8/4.                                          x = 9 ± √89 / 4.

2x² - 9x + 6, here a = 2, b = -9, c = 6.                                                    x = -b ± √b² - 4ac / 2a = -(-9) ± √(-9)² - 4(2)(6) / 2(2) = 9 ± √81 - 48/4.                                                                             x = 9 ± √33 / 4 .

5 0
3 years ago
Read 2 more answers
HELP ASAP TY DUE TMR
juin [17]

Answer:

56.55

Step-by-step explanation:

use formula

hope this helps :)

8 0
3 years ago
Read 2 more answers
8 + 3x=29 +2x <br> I need answer ASAP
borishaifa [10]

Answer:

x = 21

Step-by-step explanation:

8 + 3x = 29 + 2x

8 + 3x - 2x = 29

8 + x = 29

x = 29 - 8 = 21

x = 21

3 0
3 years ago
Jan'ai was asked to determine the minimum for a function with zeros located at –1 and 5, which also has a y-intercept of (0, –25
sergey [27]

The first error in Jan'ai's work in determining the considered function is given by: Option D: She incorrectly determined the x-coordinate of the vertex.

<h3>What are the coordinates of vertex for a quadratic function?</h3>

For a quadratic function of the form y = ax^2 + bx + c, its vertex form is obtained as:

y = ax^2 + bx + c\\y  =a(x^2 + bx/a) + c\\y = a(x^2 + 2(b/2a)x + (b/2a)^2 -(b/2a)^2  )+ c\\y = a(x^2 + 2(b/2a)x + (b/2a)^2) -a \times (b/2a)^2 + c\\\\y = a(x+b/2a)^2 - a \times (b/2a)^2 + c

For the form y = a(x-h)^2 + k, the vertex has coordinates (h, k)

Thus, for the obtained equation y = a(x+b/2a)^2 - a \times (b/2a)^2 + c, we get the coordinates of vertex as:

h = -b/2a, k = c - a\times(b/2a)^2

Thus, the coordinates of vertex of  y = ax^2 + bx + c is:

(h,k) = (-b/2a, c - a \times (b/2a)^2 )

The missing steps of work of Jan'ai are:

  1. Begin to write a function in factored form. f(x) = a(x+1)(x-5)
  2. Substitute x = 0, y = f(x) =  -25 to determine a. -25 = a(0+1)(0-5)
  3. Simplify and solve to find a. a=5
  4. Rewrite the function. f(x) = 5(x+1)(x-5)
  5. Rewrite in standard form. f(x) = 5x^2-20x-25
  6. Find the x-coordinate of the vertex. x = -20/2(5) = -20/10; x = -2
  7. Find the y-coordinate of the vertex.

y = 5x^2-20x-25

y = 5(-2)^2-20(-2)-25

y = 35

so (-2,35) is the coordinate of the vertex, which denotes the minimum.

So, as we see, in the 5th step, Jan'ai had the quadratic function f(x) = 5x^2-20x-25,

Comparing this to f(x) = ax^2 + bx + c, we get a = 5, b = -20, c = -25

The vertex's x-coordinate will be on -b/2a = -(-20)/ 2(5) = 20/10 = 2

But Jan'ai didn't putted that negative sign before b. in the 6th step.

Thus, the first error in Jan'ai's work in determining the considered function is given by: Option D: She incorrectly determined the x-coordinate of the vertex.

Learn more about the vertex form of a quadratic equation here:

brainly.com/question/9912128

6 0
3 years ago
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