Answer:
The correct option is (c).
Step-by-step explanation:
The complete question is:
The data for the student enrollment at a college in Southern California is:
Traditional Accelerated Total
Math-pathway Math-pathway
Female 1244 116 1360
Male 1054 54 1108
Total 2298 170 2468
We want to determine if the probability that a student enrolled in an accelerated math pathway is independent of whether the student is female. Which of the following pairs of probabilities is not a useful comparison?
a. 1360/2468 and 116/170
b. 170/2468 and 116/1360
c. 1360/2468 and 170/2468
Solution:
If two events <em>A</em> and <em>B</em> are independent then:

In this case we need to determine whether a student enrolled in an accelerated math pathway is independent of the student being a female.
Consider the following probabilities:

If the two events are independent then:
P (F|A) = P(F)
&
P (A|F) = P (A)
But what would not be a valid comparison is:
P (A) = P(F)
Thus, the correct option is (c).
Answer:
Multiply 1/4 ; dividing 4
Step-by-step explanation:
Note that in each number going from left to right, it decreases by dividing 4 each time (or multiplying 1/4)
8/4 = 2 ; 2/4 = 1/2 ; (1/2)/(4) = 1/8 ; etc.
(8)(1/4) = 2 ; (2)(1/4) = 1/2 ; etc.
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Answer: $6197.77 would be the right answer
hope it helps :]
Answer:
6
Step-by-step explanation:6/3= 2
Answer:
60 MPH
Step-by-step explanation: