Answer:
1) xₙ = n² - (n - 1)
2) 1/4
Step-by-step explanation:
1) 1 = 1² - (1-1)
3 = 2² - (2-1)
7 = 3² - (3-1)
13 = 4² - (4-1)
...........
xₙ = n² - (n - 1)
2) three consecutive terms of an exponential sequence: x, rx , r²x
x: 2nd term of linear sequence
rx: 6th term of linear sequence rx = x + 4d
r²x: 7th term of linear sequence r²x = rx + d d = r²x - rx
rx = x + 4 * (r²x - rx) = x + 4r²x - 4rx
4xr² -5rx + x = 0
x(4r² -5r + 1) = 0
x (4r - 1) ( r - 1) = 0
x = 0 or r = 1/4 or r = 1
if either x = 0 or r = 1 d will be equals to "0" everything became 0
So the only reasonable answer is r = 1/4
860 *11/100=9460/100=94.6
94.6 is earned
In decimal form it’s 0.3048.. so basically 0.3
Answer:
5.00 -2.40= 2.60
2.60-1.33= 1.27
The answer is 1.27
Step-by-step explanation:
Answer:
- The function f(x) = 9,000(0.95)^x represents the situation.
- After 2 years, the farmer can estimate that there will be about 8,120 bees remaining.
- The range values, in the context of the situation, are limited to whole number
Step-by-step explanation:
The "growth" rate is -5%, so the growth factor, the base in the exponential equation, is 1.00-5% =0.95.
Using x=2, we find the population in 2 years is expected to be about ...
f(2) = 9000·0.95^2 ≈ 8123 . . . . about 8120
Using x=4, we find the population in 4 years is expected to be about ...
f(4) = 9000·0.95^4 ≈ 7331 . . . . about 7330
Since population is whole numbers of bees, the range of the function is limited to whole numbers.
The domain of the function is numbers of years. Years can be divided into fractions as small as you want, so the domain is not limited to whole numbers.
The choices listed above are applicable to the situation described.
