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hichkok12 [17]
3 years ago
5

Solve the equation. 9 = 8n

Mathematics
2 answers:
KatRina [158]3 years ago
6 0

Answer:

n=1 1/8 in exact form 9/8

laila [671]3 years ago
5 0
N = 1 1/8 because divide by 8 on both sides and simplify the fraction
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A rectangular piece of metal is 20 in longer than it is wide. Squares with sides 4 in long are cut from the four corners and the
Misha Larkins [42]

Answer:

Step-by-step explanation:

This is good!  The length of the metal is 20 inches longer than the width.  But we fold up 4-inch flaps on each side, so the height of the box is 4 inches, and the length and width will each decrease by 8 inches (4 inches on each side).  Since the length and width decrease by the same amount, the length will still be 20 inches longer than the width.  So the equations would be:

l = w + 20

vol = l x w x h = 1716 in3

1716 = (w + 20)(w)(4)

1716 = 4w2 + 80w

4w2 + 80w - 1716 = 0

4(w2 + 20w - 429) = 0

4(w + 33)(w - 13) = 0

w + 33 = 0, so w = -33

w - 13 = 0, so w = 13

Since the width can't be negative, the width of the box is 13 and the length is 33 (13 + 20).

But remember, the length and width of the piece of metal are each 8 inches longer than the box, so it was 41 inches by 21 inches.

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3 years ago
Justin is considering two websites for downloading music.The costs are detailed here.
solniwko [45]

Answer:

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Step-by-step explanation:

Website 1 has upfront cost of $30.

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4 years ago
Selena played 32 games of chess. If she won x games, which expression represents her losses?
melamori03 [73]
The answer is ........ (C)
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RoseWind [281]

Answer:

x(\sqrt[12]{x^5} )

Step-by-step explanation:

We need to remember 2 rules when doing these:

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2. x^a*x^b=x^{ab}

Using these 2 rules, we can simplify the product (steps shown below):

\sqrt[3]{x^2} *\sqrt[4]{x^3} \\=x^{\frac{2}{3}}*x^{\frac{3}{4}}\\=x^{\frac{2}{3}+\frac{3}{4}}\\=x^{\frac{17}{12}}\\=x^{\frac{12}{12}+\frac{5}{12}}\\=x(x^{\frac{5}{12}})\\=x(\sqrt[12]{x^5} )

Rearranging, we see that it is the third choice.

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3 years ago
Can someone please help me with this question
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Answer:

i don't now

Step-by-step explanation:

Sorry I couldn't help you

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