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Law Incorporation [45]
3 years ago
13

Finding an Equation of a tangent Line in Exercise, find an equation of the tangent line to the graph of the function at the give

n point.
g(x) = e^x3 , (-1,1/e)
Mathematics
1 answer:
frutty [35]3 years ago
3 0

Answer:

y=\dfrac{3x}{e}+\dfrac{4}{e}

this is the equation of the tangent at point (-1,1/e)

Step-by-step explanation:

to find the tangent line we need to find the derivative of the function g(x).

g(x) =e^{x^3}

  • we know that \frac{d}{dx}(e^{f(x)})=e^{f(x)}f'(x)

g'(x) =e^{x^{3}}(3 x^{2})

g'(x) =3 x^{2} e^{x^{3}}

this the equation of the slope of the curve at any point x and it also the slope of the tangent at any point x. hence, g'(x) can be denoted as 'm'

to find the slope at (-1,1/e) we'll use the x-coordinate of the point i.e. x = -1

m =3 (-1)^{2} e^{(-1)^{3}}\\m =3e^{-1}\\m=\dfrac{3}{e}

using the equation of line:

(y-y_1)=m(x-x_1)

we'll find the equation of the tangent line.

here (x1,y1) =(-1,1/e), and m = 3/e

(y-\dfrac{1}{e})=\dfrac{3}{e}(x+1)\\y=\dfrac{3x}{e}+\dfrac{3}{e}+\dfrac{1}{e}\\

y=\dfrac{3x}{e}+\dfrac{4}{e}

this is the equation of the tangent at point (-1,1/e)

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Quiana took out a loan to pay for a new car initially she owed the lender 15,234.68. she has repaid 247.43 of the loan each mont
Serga [27]

Given Information:

Initial amount of loan = $15,234.68

Monthly payment = $247.43

Number of months = 5

Required Information:

Net change in loan = ?

Answer:

Net change in loan = $1,237.15 = $1,237(3/20)

Step-by-step explanation:

Quiana owed her lender an amount of 15,234.68 initially, she repaid the lender each month with an amount of $247.43 for 5 months, so the total amount that she repaid is

Total amount repaid = Monthly payment*Number of months

Total amount repaid = $247.43 × 5

Total amount repaid = $1,237.15

The remaining owed amount is given by

Balance = Initial amount of loan - Total amount repaid

Balance = $15,234.68 - $1237.15

Balance = $13,997.53

So the net change to the loan from Quiana's perspective over the past 5 months is,

Net change in loan = Initial amount of loan - Balance

Net change in loan = $15,234.68 - $13,997.53

Net change in loan = $1,237.15

or

Net change in loan = $1,237(3/20)

Therefore, the net change to the loan from Quiana's perspective over the past 5 months is $1,237.15

6 0
3 years ago
Is this right I'm practicing multiplying decimals by 10, 100, or 1,000
Leokris [45]
All are correct except the bottom, it would just be 4.23 since there are no zeroes, any number times 1 is itself
8 0
3 years ago
Look at the number sentence below. -26 + 75 =
Novosadov [1.4K]
-26+75=43 hope this helps


3 0
4 years ago
Construct a triangle STU in which<br>LT=60o Lu=70° and TU = 7.5 cm<br>60°​
disa [49]
Ok first you have to multiply and get scammed
6 0
3 years ago
Solve x <br><br> 4x-5 /5 = 3
cluponka [151]

Answer:

x = 1

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

4x−

5

5

=3

4x+−1=3

4x−1=3

Step 2: Add 1 to both sides.

4x−1+1=3+1

4x=4

Step 3: Divide both sides by 4.

4x

4

=

4

4

x=1

6 0
3 years ago
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