A and B Definitely. 3 and 17, -3 and -17
Answer:
a. y = (3/5)× x +1
Step-by-step explanation:
y= mx+c
m = (13-4)/(20-5) = 9/15 = 3/5
c= 1
so, y= mx+c becomes y= (3/5) × x +1
The answer should be 74% probability
35/50+5/50-3/50= 37/50->74%
For this case, the first thing we are going to do is assume that all the tests are worth the same.
Then, we define a variable:
x: score of Mona's last test
We write now the inequality that models the problem:

From here, we clear the value of x:
Answer:
the lowest grade that Mona can get for her last test so that her test average is 90 or more is:
x = 87