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Pani-rosa [81]
3 years ago
6

The square of a positive number decreased by twice the number is 48. Find the number

Mathematics
2 answers:
o-na [289]3 years ago
8 0
X^2=2x+48
x^2-2x-48=0
(x-8)(x+6)=0
x=8 x=-6
x must be negative so x=-6
check 
36=48+-12
36=36
KIM [24]3 years ago
6 0

Let the required positive number is x.

The square of the number is x^2

Now, we have been given that square of a positive number decreased by twice the number. It means we have

x^2-2x

Now, it is equal to 48. Hence, we have

x^2-2x=48\\
x^2-2x-48=0\\
x^2-8x+6x-48=0\\
x(x-8)+6(x-8)\\
(x-8)(x+6)=0\\
x=8,-6

The number is positive, Hence, we have x=8

Therefore, the required number is 8

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