





With the initial condition
, we find



So the particular solution to the IVP is

Answer:
8.89 feet
Step-by-step explanation:
The square of the side length is 79 ft², so the side length is the square root of that:
√(79 ft²) ≈ 8.88819 ft ≈ 8.89 ft
Answer:
MAKE IT BIGGER
Step-by-step explanation:
Answer:

Step-by-step explanation:
Solve the inequality 
Use distributive property:

Subtract 4s:

Subtract 14:

Divide by -6 (do not forget to change sign, because division by negative number changes the sign):
