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Fynjy0 [20]
4 years ago
10

140 apples fall on the ground in 35 Seconds how many apples fall in 1 second

Mathematics
2 answers:
snow_tiger [21]4 years ago
8 0
140a/35s=4a/s

.......................
Lubov Fominskaja [6]4 years ago
5 0
140 divided by 35, 4 fall per second.
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What if it was for 20 months
olya-2409 [2.1K]

Answer:

dont really understand your question but 20 months is

608.334 days and 86.9049 months

6 0
3 years ago
An electronics company has developed a new hand held device. The company predicts that the start up cost to manufacture the new
alex41 [277]
Profit = revenue - expenses

expenses : 125,000 + 6.50x
revenue : 9x
so to make a profit, ur revenue (income) has to be higher then ur expenses

revenue > expenses
A. ) 9x > 125,000 + 6.50x
9x - 6.50x > 125,000
2.5x > 125,000
x > 125,000 / 2.5
x > 50,000......so they would have to sell at least 50,001 devices to make a profit <==

B.) the cost of making 1 device is 10% more then the company predicted....10% more then 6.50.....6.50(1.10) = 7.15.....this is the new cost of making 1 device <==

9x > 125,000 + 7.15x ....this is the inequality with the 10% more added
9x - 7.15x > 125,000
1.85x > 125,000
x > 125,000 / 1.85
x > 67,567.5......so to make a profit, they would have to sell at least 67,568 devices to make a profit <==


7 0
3 years ago
Solve the equation without the use of a calculator. please Help!!! Thank you!!!<br> 5=2x^2+3
Olin [163]
Solving for X.

5 = 2x^2 + 3 Subtract 3 from both sides.

2 = 2x^2 Divide by 2 on both sides.

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X = 1
8 0
4 years ago
Consider a particle moving along the x-axis where x(t) is the position of the particle at time t, x' (t) is its velocity, and x'
vodka [1.7K]

Answer:

a) v(t) =x'(t) = \frac{dx}{dt} = 3t^2 -12t +9

a(t) = x''(t) = v'(t) =6t-12

b)  0

c) a(t) = x''(t) = v'(t) =6t-12

When the acceleration is 0 we have:

6t-12=0, t =2

And if we replace t=2 in the velocity function we got:

v(t) = 3(2)^2 -12(2) +9=-3

Step-by-step explanation:

For this case we have defined the following function for the position of the particle:

x(t) = t^3 -6t^2 +9t -5 , 0\leq t\leq 10

Part a

From definition we know that the velocity is the first derivate of the position respect to time and the accelerations is the second derivate of the position respect the time so we have this:

v(t) =x'(t) = \frac{dx}{dt} = 3t^2 -12t +9

a(t) = x''(t) = v'(t) =6t-12

Part b

For this case we need to analyze the velocity function and where is increasing. The velocity function is given by:

v(t) = 3t^2 -12t +9

We can factorize this function as v(t)= 3 (t^2- 4t +3)=3(t-3)(t-1)

So from this we can see that we have two values where the function is equal to 0, t=3 and t=1, since our original interval is 0\leq t\leq 10 we need to analyze the following intervals:

0< t

For this case if we select two values let's say 0.25 and 0.5 we see that

v(0.25) =6.1875, v(0.5)=3.75

And we see that for a=0.5 >0.25=b we have that f(b)>f(a) so then the function is decreasing on this case.  

1

We have a minimum at t=2 since at this value w ehave the vertex of the parabola :

v_x =-\frac{b}{2a}= -\frac{-12}{2*3}= -2

And at t=-2 v(2) = -3 that represent the minimum for this function, we see that if we select two values let's say 1.5 and 1.75

v(1.75) =-2.8125< -2.25= v(1.5) so then the function sis decreasing on the interval 1<t<2

2

We see that the function would be increasing.

3

For this interval we will see that for any two points a,b with a>b we have f(a)>f(b) for example let's say a=3 and b =4

f(a=3) =0 , f(b=4) =9 , f(b)>f(a)

The particle is moving to the right then the velocity is positive so then the answer for this case is: 0

Part c

a(t) = x''(t) = v'(t) =6t-12

When the acceleration is 0 we have:

6t-12=0, t =2

And if we replace t=2 in the velocity function we got:

v(t) = 3(2)^2 -12(2) +9=-3

5 0
3 years ago
"The sum of a number and 4."
kenny6666 [7]

Answer:

n + 4

Step-by-step explanation:

It´s like a normal sum, but since the number is unknown just put n.

7 0
4 years ago
Read 2 more answers
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