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3 years ago

Help please & thank you :)

Mathematics

1 answer:

zysi [14]3 years ago

6 0

Answer:

3x-5y=22

3x-5*(32-5x)=22

3x-5*32+5*5x=22

3x-160+25x=22

28x=22+160

28x=182

x=182/28

x=6.5

y=32-5x=32-5*6.5=32-32,5= -0.5

Multiply the first equation with 5 and the second with (-3)

Step-by-step explanation:

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kumpel [21]

Answer:

$(x+4)^2+(y-3)^2=149$

Step-by-step explanation:

The equation of a circle is $(x-h)^2+(y-k)^2=r^2$ where $(h,k)$ is the center of the circle and $r$ is the radius of the circle.

Given that $(h,k)\rightarrow(-4,3)$ and it passes $(6,-4)$ , their distance between each other must the radius of the circle, so we can use the distance formula to find the radius:

$d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}\\\\d=\sqrt{(-4-3)^2+(6-(-4))^2}\\\\d=\sqrt{(-7)^2+10^2}\\\\d=\sqrt{49+100}\\\\d=\sqrt{149}$

Therefore, if the length of the radius is $r=\sqrt{149}$ units, then $r^2=149$ , making the final equation of the circle $(x+4)^2+(y-3)^2=149$

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3 years ago

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Step-by-step explanation:

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Step-by-step explanation:

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